(a) V = kN. (b) V = kN. (c) V = kN. (d) V = kN
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Determine the shear force acting at each of the following locations:
(a) x = 0+ m (i.e., just to the right of fixed support A)
(b) x = 3.5– m (i.e., just to the left of B)
(c) x = 3.5+ m (i.e., just to the right of B)
(d) x = 5.0– m (i.e., just to the left of C)
When entering your answers, use the shear force sign convention.
Answer:
(a) V = kN.
(b) V = kN.
(c) V = kN.
(d) V = kN.
(a) x = 0+ m (i.e., just to the right of fixed support A)
(b) x = 3.5– m (i.e., just to the left of B)
(c) x = 3.5+ m (i.e., just to the right of B)
(d) x = 5.0– m (i.e., just to the left of C)
When entering your answers, use the shear force sign convention.
Answer:
(a) V = kN.
(b) V = kN.
(c) V = kN.
(d) V = kN.
Determine the bending moment acting at each of the following locations:
(a) x = 0+ m (i.e., just to the right of fixed support A)
(b) x = 3.5– m (i.e., just to the left of B)
(c) x = 3.5+ m (i.e., just to the right of B)
(d) x = 5.0 m
When entering your answers, use the bending moment sign convention.
Answers:
(a) M = kN-m.
(b) M = kN-m.
(c) M = kN-m.
(d) M = kN-m.
(a) x = 0+ m (i.e., just to the right of fixed support A)
(b) x = 3.5– m (i.e., just to the left of B)
(c) x = 3.5+ m (i.e., just to the right of B)
(d) x = 5.0 m
When entering your answers, use the bending moment sign convention.
Answers:
(a) M = kN-m.
(b) M = kN-m.
(c) M = kN-m.
(d) M = kN-m.

Transcribed Image Text:Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=1.5 m,
Pg = 4 kN, Pc = 4 kN, and Mg = 40 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to
answer the questions in the subsequent parts of this GO exercise.
PB
Pc
MB
C
b
Calculate the reaction forces Ay and Ma acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since A, = 0, it has been omitted from the free-body diagram.)
PB
PC
MA
MB
B
C
b
Answers: Ay=
i
kN, MA =
i
kN-m.
%3D
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