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average molarity of NaOH (from part A), M 0.5507 m NaDH HC,H,0,(aq) + NaOH(aq) -→ H,O(1) + NaC,H,O,(aq) Trial 1 Trial 2 volume of vinegar, mL 10.00 mL 10.00 mL volume of vinegar, L initial buret reading, mL 0.00 mL 0.00mL final buret reading, mL 38.50 mL るい50mL volume of NaOH, mL 38.50mh 36.50mL volume of NaOH, L 0.0383 mL 0.03し5 レ moles of NaOH, mol moles of HC,H,O,(aq), mol (HC,H,0,(aq)], M average [HC,H,O,(aq)], M

average molarity of NaOH (from part A), M 0.5507 m NaDH HC,H,0,(aq) + NaOH(aq) -→ H,O(1) + NaC,H,O,(aq) Trial 1 Trial 2 volume of vinegar, mL 10.00 mL 10.00 mL volume of vinegar, L initial buret reading, mL 0.00 mL 0.00mL final buret reading, mL 38.50 mL るい50mL volume of NaOH, mL 38.50mh 36.50mL volume of NaOH, L 0.0383 mL 0.03し5 レ moles of NaOH, mol moles of HC,H,O,(aq), mol (HC,H,0,(aq)], M average [HC,H,O,(aq)], M

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Quantitative Analysis of Vinegar via Titration Report Sheet 2 Part B: Analysis of Vinegar average molarity of NaOH (from part A), M 0.5501 m NADH HC,H,0,(aq) + NaOH(aq) -→ H,O(1) + NaC,H,0,(aq) Trial 1 Trial 2 Trial 3 volume of vinegar, mL 10.00 mL 10.00 mL volume of vinegar, L initial buret reading, mL 0.00 mL 0.00mL final buret reading, mL 38.50 mL る6、50mL volume of NaOH, mL 38.50mh 36.50mL volume of NaOH, L 0.0383 mL 0.03し5 。 moles of NaOH, mol moles of HC,H,O,(aq), mol [HC,H,0,(aq)], M average (HC,H,O,(aq)], M Show calculations and calculate the mass percent concentration of HC HO, on the back of this page.
Transcribed Image Text:Quantitative Analysis of Vinegar via Titration Report Sheet 2 Part B: Analysis of Vinegar average molarity of NaOH (from part A), M 0.5501 m NADH HC,H,0,(aq) + NaOH(aq) -→ H,O(1) + NaC,H,0,(aq) Trial 1 Trial 2 Trial 3 volume of vinegar, mL 10.00 mL 10.00 mL volume of vinegar, L initial buret reading, mL 0.00 mL 0.00mL final buret reading, mL 38.50 mL る6、50mL volume of NaOH, mL 38.50mh 36.50mL volume of NaOH, L 0.0383 mL 0.03し5 。 moles of NaOH, mol moles of HC,H,O,(aq), mol [HC,H,0,(aq)], M average (HC,H,O,(aq)], M Show calculations and calculate the mass percent concentration of HC HO, on the back of this page.
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