ation of Reaction Times tration of Na S0, 0.02 Volume of Na,S,0, (L)_O.001L Ambient temperature, tration of KI_O. M ; Molar concentration of H,O, 0.1 M: Total volume of kinetic trials (mL), イ color ar (sec) ons for Determining the Rate Law S,O, produced S- S- S- (yow) - - 6.857 (TE (7) 1 3.0 ** 0.9 -0.046 0.3 ** -0.52 for Kinetic Trial 1. ial molar concentration.
Electronic Effects
The effect of electrons that are located in the chemical bonds within the atoms of the molecule is termed an electronic effect. The electronic effect is also explained as the effect through which the reactivity of the compound in one portion is controlled by the electron repulsion or attraction producing in another portion of the molecule.
Drawing Resonance Forms
In organic chemistry, resonance may be a mental exercise that illustrates the delocalization of electrons inside molecules within the valence bond theory of octet bonding. It entails creating several Lewis structures that, when combined, reflect the molecule's entire electronic structure. One Lewis diagram cannot explain the bonding (lone pair, double bond, octet) elaborately. A hybrid describes a combination of possible resonance structures that represents the entire delocalization of electrons within the molecule.
Using Molecular Structure To Predict Equilibrium
Equilibrium does not always imply an equal presence of reactants and products. This signifies that the reaction reaches a point when reactant and product quantities remain constant as the rate of forward and backward reaction is the same. Molecular structures of various compounds can help in predicting equilibrium.
Please help me with Trial 4 it is highlighted.
![A. Determination of Reaction Times
Molar concentration of Na SO, 0.02
;Volume of Na,S,0, (L)_O.001L Ambient temperature
"C
Molar concentration of KI O. 5 M; Molar concentration of H,O,
Total volume of kinetic trials (mL)
Kin etic Trial
イ
1. Time for color
change, Ar (sec)
25
B. Calculations for Determining the Rate Law
1. Moles of S,0,
gou) pounsuoo
8-30t s- 10°
2. A(mol I,) produced
S-
S-
S-
A(mol I, )
3.
t-
1.38E*
8.0E
(yyou)
-6.857
-6.857.
801
5. Volume KI (ml.)
3.0
10
0.9
**
7. log [1],
8. Volume HaOa CmL)
-0.046
0.3
'6
**
-6,52
*Calculations for Kinetic Trial 1.
*Diluted initial molar concentration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ffcae09-aa93-4006-b426-86514542bb71%2F4ae7d276-f478-4dc2-b5a4-f59860de07ef%2Frjf1k7_processed.jpeg&w=3840&q=75)
Given: Table
To find: To complete the given table
Solution: Molarity is defined as the ratio of number of moles to the volume in Liters. Molarity can be calculated by using the formula:
M=n/V(L)
Where M is molarity
n is number of moles
V is volume in Liters
Number of moles can be defined as the ratio of given mass to the molar mass. Number of moles can be calculated by using the formula which is shown below:
n=m/M
Where n is number of moles
m is given mass
M is molar mass
According to the law of equivalence we can say that
M1V1= M2V2
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