at sort of a loss on how to go about the last request on this lab assignment (Line 16 in the screen shot). If I run the matlab code as it's seen, it runs perfectly. Once I comment out line 2, uncomment line 4 and run that, I get a bunch of errors after Matrix A is displayed. Does anyone have insight on what the professor might be asking here? Does line 7 need to be changed because of Matrix A being changed? I only need help with the sections noted with red. Thanks.
at sort of a loss on how to go about the last request on this lab assignment (Line 16 in the screen shot). If I run the matlab code as it's seen, it runs perfectly. Once I comment out line 2, uncomment line 4 and run that, I get a bunch of errors after Matrix A is displayed. Does anyone have insight on what the professor might be asking here? Does line 7 need to be changed because of Matrix A being changed? I only need help with the sections noted with red. Thanks.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I'm at sort of a loss on how to go about the last request on this lab assignment (Line 16 in the screen shot).
If I run the matlab code as it's seen, it runs perfectly. Once I comment out line 2, uncomment line 4 and run that, I get a bunch of errors after Matrix A is displayed. Does anyone have insight on what the professor might be asking here? Does line 7 need to be changed because of Matrix A being changed? I only need help with the sections noted with red. Thanks.
![Utilize the following linear system of equations for this activity.
-2x, +x2 + 2x3 = 0
X1 + 3x2 + 2x3 =-4
3x1 – x2 + x3 = 3
Before submitting your solution, consider repeating the work above with the coefficient matrix A = [-2 1 2; 1 3 2; -14 4]. Do you run into
any difficulties or errors when finding the solution? Explain what is happening as a comment in your code.
Script e
A Save
C Reset
I MATLAB Documentation
1 %Create the coefficient matrix.
Store the coefficient matrix in A.
2 A = [-2 1 2; 1 3 2; 3 -1 1]
3
4 %A = [-2 1 2; 1 3 2; -1 4 4]
6 %Create the column matrix of constants.
Store the column matrix of constants in b.
7 b = [0; -4; 3]
8
9 %Use the inv() command to find the inverse of the matrix A.
Store the inverse matrix in invA.
10 invA = inv (A)
11
12 %Find the solution to the linear system of equations using the inverse matrix, if the inverse matrix
13 %exists.
If the inverse matrix exists, store the solution to the linear system of equations in x.
14
x = invA * b
16 %Before submitting your solution, consider repeating the work above with the coefficient matrix A = [-2 1 2; 1 3
18
19](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa574c461-0cd6-47ac-ac88-e1c1ab5a9198%2F91a610ea-3793-41ff-abc6-3821ca7cb156%2Fofaaub8_processed.png&w=3840&q=75)
Transcribed Image Text:Utilize the following linear system of equations for this activity.
-2x, +x2 + 2x3 = 0
X1 + 3x2 + 2x3 =-4
3x1 – x2 + x3 = 3
Before submitting your solution, consider repeating the work above with the coefficient matrix A = [-2 1 2; 1 3 2; -14 4]. Do you run into
any difficulties or errors when finding the solution? Explain what is happening as a comment in your code.
Script e
A Save
C Reset
I MATLAB Documentation
1 %Create the coefficient matrix.
Store the coefficient matrix in A.
2 A = [-2 1 2; 1 3 2; 3 -1 1]
3
4 %A = [-2 1 2; 1 3 2; -1 4 4]
6 %Create the column matrix of constants.
Store the column matrix of constants in b.
7 b = [0; -4; 3]
8
9 %Use the inv() command to find the inverse of the matrix A.
Store the inverse matrix in invA.
10 invA = inv (A)
11
12 %Find the solution to the linear system of equations using the inverse matrix, if the inverse matrix
13 %exists.
If the inverse matrix exists, store the solution to the linear system of equations in x.
14
x = invA * b
16 %Before submitting your solution, consider repeating the work above with the coefficient matrix A = [-2 1 2; 1 3
18
19
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