Prove Boolean Equation: (A'B')'+D'=A+(BD)'
Prove Boolean Equation: (A'B')'+D'=A+(BD)'
Boolean algebra is a fundamental branch of mathematics used in digital logic and computer science to manipulate and simplify logical expressions. Proving Boolean equations is a common practice to establish the equivalence of two logical expressions. In this context, we will prove the Boolean equation using Boolean algebra laws and simplification techniques. The goal is to demonstrate that these two expressions are equivalent through step-by-step transformations.
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Thank you. I can see that you have now applied De Morgan's the same way I do (I'm still confused as to how you were applying it previously). However, for the line suggesting that we apply the Boolean identity X+X'=1, with X equaling A+B, I would have expected to see (A+B)+(A+B)' being applied somewhere, which I don't. The equation is simply rewritten with no changes (no applications of an identity) at all. Could you please show how this identity was applied so that I can understand it? Thanks, again.
by Bartleby ExpertStill not getting how you are applying De Morgan's Law. (A'B')' would be A''+B'', which would simplify to A+B, and (BD)' would be B'+D'. However, you are getting A'+B and B'+D instead. Yet, you say I am right even though we get different expressions. This is very confusing. Are you skipping (not showing) some steps?
by Bartleby ExpertAccording to De Morgan's Law, (A'B')' would be A''+B'', which would simplify to A+B, and (BD)' would be B'+D'. This much I think I'm pretty solid on. However, if I'm correct, it makes the given solution completely incorrect. There are a lot of other parts of the given solution that are very unclear as well. Please try again with better explanations and showing of work. Thank you...
by Bartleby Expert
