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At a nearby college, there is a school-sponsored website that matches people looking for roommates. According ta the school's reports, 43% af students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample aof 170 students who visited the site looking for a roommate. Of the students surveyed, 58 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level af significance, to reject the ciaim that the proportion, P, of all students who will find a match their first time using the site is 43%. (a) State the null hypothesis A and the alternative hypothesis H that you wauld use for the test. H 0 (b) For your hypothesis test, you will use a Z-test. Find the values of P and n(1-p) to confirm that a Z-test can be used. (One standard is that p2 10 and 4(1-9)2 10 under the assumption that the null hypothesis is true.) Here is the sample size and P is the papulation proportion you are testing. (1-7) =0 (c) Perform a Z-test. Here is some information to help you with your Z-test. • F0.as is the value that cuts off an area of 0.05 in the right tail of the distribution. • The value of the test statistic is given by = Standard Normal Distribution Step 1: Seect one-taiked or two-lailed. O One-taiked O Two-lalud Stap 2: Enter the critical valau(s). (Round to 3 decimal places.) Stap 3: Enter the test statistic. (ound to 3 decimal places.) 8 會 回

At a nearby college, there is a school-sponsored website that matches people looking for roommates. According ta the school's reports, 43% af students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample aof 170 students who visited the site looking for a roommate. Of the students surveyed, 58 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level af significance, to reject the ciaim that the proportion, P, of all students who will find a match their first time using the site is 43%. (a) State the null hypothesis A and the alternative hypothesis H that you wauld use for the test. H 0 (b) For your hypothesis test, you will use a Z-test. Find the values of P and n(1-p) to confirm that a Z-test can be used. (One standard is that p2 10 and 4(1-9)2 10 under the assumption that the null hypothesis is true.) Here is the sample size and P is the papulation proportion you are testing. (1-7) =0 (c) Perform a Z-test. Here is some information to help you with your Z-test. • F0.as is the value that cuts off an area of 0.05 in the right tail of the distribution. • The value of the test statistic is given by = Standard Normal Distribution Step 1: Seect one-taiked or two-lailed. O One-taiked O Two-lalud Stap 2: Enter the critical valau(s). (Round to 3 decimal places.) Stap 3: Enter the test statistic. (ound to 3 decimal places.) 8 會 回

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 43% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 170 students who visited the site looking for a roommate. Of the students surveyed, 58 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that the proportion, P, of all students who will find a match their first time using the site is 43%. (a) State the null hypothesis H, and the alternative hypothesis A that you would use for the test. P H 0 D=0 DO (b) For your hypothesis test, you will use a Z-test. Find the values of MP and n(1-p) to confirm that a Z-test can be used. (One standard is that Mp2 10 10 under the assumption that the null hypothesis is true.) Here is the sample size and P is the population proportion you are testing. and np = 0 a (1-p) = 0 (c) Perform a Z-test. Here is some information to help you with your Z-test. . hos is the value that cuts off an area of 0.05 in the right tail of the distribution. The value of the test statistic is given by = Standard Normal Distribution Step 1: Sekect one-Laiked or two-lailed. O One-Laiked O Two-laled Step 2: Enter the cral val(s). (ound to 3 decimal places.) Step 3: Enter the test statistic. (ound to 3 decimal places.) (d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made In the school's reports. ? O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will find a match their first time using the site. O Since the value of the test statistic lies in the rejection region, the null hypathesis is not rejected. So, there is not enough evidence to reject the claim that 43% of students will find a match their first time using the site. O Iince the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will finda match their first time using the site. O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is not enaugh evidence to reject the claim that 45% of students will find a match their first time using the ste.
Transcribed Image Text:At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 43% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 170 students who visited the site looking for a roommate. Of the students surveyed, 58 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that the proportion, P, of all students who will find a match their first time using the site is 43%. (a) State the null hypothesis H, and the alternative hypothesis A that you would use for the test. P H 0 D=0 DO (b) For your hypothesis test, you will use a Z-test. Find the values of MP and n(1-p) to confirm that a Z-test can be used. (One standard is that Mp2 10 10 under the assumption that the null hypothesis is true.) Here is the sample size and P is the population proportion you are testing. and np = 0 a (1-p) = 0 (c) Perform a Z-test. Here is some information to help you with your Z-test. . hos is the value that cuts off an area of 0.05 in the right tail of the distribution. The value of the test statistic is given by = Standard Normal Distribution Step 1: Sekect one-Laiked or two-lailed. O One-Laiked O Two-laled Step 2: Enter the cral val(s). (ound to 3 decimal places.) Step 3: Enter the test statistic. (ound to 3 decimal places.) (d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made In the school's reports. ? O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will find a match their first time using the site. O Since the value of the test statistic lies in the rejection region, the null hypathesis is not rejected. So, there is not enough evidence to reject the claim that 43% of students will find a match their first time using the site. O Iince the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will finda match their first time using the site. O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is not enaugh evidence to reject the claim that 45% of students will find a match their first time using the ste.
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