At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 38% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 165 students who visited the site looking for a roommate. Of the students surveyed, 48 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that the proportion, p, of all students who will find a match their first time using the site is 38%. (a) State the null hypothesis Ho and the alternative hypothesis H, that you would use for the test.

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# Introduction to Hypothesis Tests for a Population Proportion

At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 38% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 165 students who visited the site looking for a roommate. Of the students surveyed, 48 said they found a match their first time using the site.

Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that the proportion, \( p \), of all students who will find a match their first time using the site is 38%.

### (a) State the Null Hypothesis \( H_0 \) and the Alternative Hypothesis \( H_1 \) that you would use for the test.
- **Null Hypothesis \( H_0 \):**  \( p = 0.38 \)
- **Alternative Hypothesis \( H_1 \):**  \( p \neq 0.38 \)

### (b) For your hypothesis test, you will use a Z-test. Find the values of \( np \) and \( n(1-p) \) to confirm that a Z-test can be used.
(One standard is that \( np \geq 10 \) and \( n(1-p) \geq 10 \) under the assumption that the null hypothesis is true.)
- \( np = 165 \times 0.38 = 62.7 \)
- \( n(1-p) = 165 \times (1 - 0.38) = 102.3 \)

### (c) Perform a Z-test and find the \( p \)-value. 

Here is some information to help you with your Z-test:

- The value of the test statistic is given by 
\[ 
\hat{p} = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} 
\]
- The \( p \)-value is two times the area under the curve to the left of the value of the test statistic.

### Diagram
There is a diagram showing the "Standard Normal Distribution." This diagram illustrates the normal curve with sections marked under the curve to represent areas related to the test statistic and corresponding \(
Transcribed Image Text:# Introduction to Hypothesis Tests for a Population Proportion At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 38% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 165 students who visited the site looking for a roommate. Of the students surveyed, 48 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that the proportion, \( p \), of all students who will find a match their first time using the site is 38%. ### (a) State the Null Hypothesis \( H_0 \) and the Alternative Hypothesis \( H_1 \) that you would use for the test. - **Null Hypothesis \( H_0 \):** \( p = 0.38 \) - **Alternative Hypothesis \( H_1 \):** \( p \neq 0.38 \) ### (b) For your hypothesis test, you will use a Z-test. Find the values of \( np \) and \( n(1-p) \) to confirm that a Z-test can be used. (One standard is that \( np \geq 10 \) and \( n(1-p) \geq 10 \) under the assumption that the null hypothesis is true.) - \( np = 165 \times 0.38 = 62.7 \) - \( n(1-p) = 165 \times (1 - 0.38) = 102.3 \) ### (c) Perform a Z-test and find the \( p \)-value. Here is some information to help you with your Z-test: - The value of the test statistic is given by \[ \hat{p} = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} \] - The \( p \)-value is two times the area under the curve to the left of the value of the test statistic. ### Diagram There is a diagram showing the "Standard Normal Distribution." This diagram illustrates the normal curve with sections marked under the curve to represent areas related to the test statistic and corresponding \(
**Standard Normal Distribution**

**Step 1:** Select one-tailed or two-tailed.  
- O One-tailed  
- O Two-tailed  

**Step 2:** Enter the test statistic.  
*(Round to 3 decimal places.)*  
[Text Box]  

**Step 3:** Shade the area represented by the *p*-value.  
[Button with Diamond Icon]  

**Step 4:** Enter the *p*-value.  
*(Round to 3 decimal places.)*  
[Text Box]  

---

**Graph Description:**  
The graph is a standard normal distribution curve, symmetrical around the vertical axis at 0. It spans from approximately -3 to +3 on the horizontal axis, with the highest point at 0. The vertical axis represents probability density, with markings roughly at 0.1, 0.2, and 0.3. The curve demonstrates a bell shape typical of normal distributions.

---

**(d)** Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the claim made in the school's reports.  

- O Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site.  

- O Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site.  

- O Since the *p*-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site.  

- O Since the *p*-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site.
Transcribed Image Text:**Standard Normal Distribution** **Step 1:** Select one-tailed or two-tailed. - O One-tailed - O Two-tailed **Step 2:** Enter the test statistic. *(Round to 3 decimal places.)* [Text Box] **Step 3:** Shade the area represented by the *p*-value. [Button with Diamond Icon] **Step 4:** Enter the *p*-value. *(Round to 3 decimal places.)* [Text Box] --- **Graph Description:** The graph is a standard normal distribution curve, symmetrical around the vertical axis at 0. It spans from approximately -3 to +3 on the horizontal axis, with the highest point at 0. The vertical axis represents probability density, with markings roughly at 0.1, 0.2, and 0.3. The curve demonstrates a bell shape typical of normal distributions. --- **(d)** Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the claim made in the school's reports. - O Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site. - O Since the *p*-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site. - O Since the *p*-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 38% of students will find a match their first time using the site. - O Since the *p*-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 38% of students will find a match their first time using the site.
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