Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feelingmore enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out onyour own. You randomly survey 64 of her past Elementary Statistics students and find that 35 feel more enriched as a result ofher class. Now, what do you think? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normallydistributed. (In general, you must first prove that assumption, though.)Part (a)Part (b)Part (c)Part (d)Part (e)Part (f)Part (g)Part (h)Part (i)Construct a 95% confidence interval for the true proportion. Sketch the graph of the situation. Label the point estimate and the lower and upperbounds of the confidence interval. (Round your answers to four decimal places.)95% C.I.Viewing Saved Work Revert to Last Response

Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics…

Answered: Construct a 95% confidence interval for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The 90% confidence interval for the population proportion p is The 95% confidence interval for the population proportion p is With the given confidence, it can be said that the of adults who say they have made a New Year's resolution is of the given confidence interval. Compare the widths of the confidence intervals. Choose the correct answer below. A. The 90% confidence interval is wider. B. The 95% confidence interval is wider. C. The confidence intervals are the same width. D. The confidence intervals cannot be compared.
Decreasing the sample size while the confidence level remains the same, will do what to the length of your confidence interval? A. cannot be determined from the given information B. make it bigger C. it will stay the same D. make it smaller
Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 2.9 to 4.3 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. C Choose the correct answer below. O A. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the probability it does not contain the true value of the population mean is also 5%. O B. The statement does not make sense. The population mean is a fixed constant that either falls within the confidence interval or it does not. There is no probability associated with this. O C. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is…
Which is TRUE about a 99% confidence interval based on a given sample? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. The interval contains 99% of the population. a The interval is wider than a 95% confidence interval would be. The interval is wider than a 100% confidence interval would be. d Results from 99% of all samples will lie in this interval.
Use the confidence interval to find the margin of error and the sample mean. (0.614,0.690) The margin of error is The sample mean is
K A R Explain how finding a confidence interval for a population variance is different from finding a confidence interval for a population mean or proportion. Choose the correct answer below. OA. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must be calculated separately. OB. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must not be calculated separately OC. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right endpoints must not be calculated separately OD. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right…
Mark each statement TRUE or FALSE. For these problems, assume that to estimate average time spent waiting at a restaurant, you sample 10 people and you get a 95% confidence interval of (5, 7) in minutes. If you increase sample size, the width of your confidence interval increases. If you increase confidence level, the width of your confidence interval increases.
In a survey of 2269 adults, 701 say they believe in UFOs. Construct a 95% confidence interval for the population proportion of adults who believe in UFOs. A 95% confidence interval for the population proportion is (nothing,nothing). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 95% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. B. The endpoints of the given confidence interval shows that 95% of adults believe in UFOs. C. With 95% confidence, it can be said that the sample proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. D. With 95% probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval.
Gonstruct a 90% confidence interval for the population mean. The 90% confidence interval is (____, ____). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean The 95% confidence interval is (____, ____). (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. A. With 90% confidence. it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is narrower than the on% B. With 90% confidence. it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is wider than the 90% C. With 90% confidence, it can be said that the sample mean price lies in the first interval. With 95% confidence, it can be said that the sample mean price…
In a survey of 2295 adults, 746 say they believe in UFOs. Construct a 90% confidence interval for the population proportion of adults who believe in UFOs. A 90% confidence interval for the population proportion is (nothing,nothing). (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 90% confidence, it can be said that the sample proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. B. The endpoints of the given confidence interval shows that 90% of adults believe in UFOs. C. With 90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. D. With 90% probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval.
Question Emilio wants to estimate the percentage of people who have a financial adviser. He surveys 350 individuals and finds that 76 have a financial adviser. Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval. Z0.10 Z0.05 Z0.025 Z0.01 Z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of common z-scores above. • Round the final answer to three decimal places. Provide your answer below: Next « Previous DII DD 80 F9 F10 F11 F12 F5 F7 F8 F3 F4
Translate the statement into a confidence interval. Approximate the level of confidence. In a survey of 1011 parents of children ages 8-14, 70% say they are willing to get a second or part-time job to pay for their children's college education and 42% say they lose sleep worrying about college costs. The survey's margin of error is +2%. Use the results from the survey about getting a second or part-time job. The confidence interval for the proportion is ( D (Round to three decimal places as needed.)

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Construct a 95% confidence interval for the true proportion. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your answers to four decimal places.)