(d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made in the school's reports. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 39% of students will find a match their first time using the site. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 39% of students will find a match their first time using the site. O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 39% of students will find a match their first time using the site. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 39% of students will find a match their first time using the site.

MATLAB: An Introduction with Applications
6th Edition
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Chapter1: Starting With Matlab
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100%
Standard Normal Distribution
Step 1: Select one-tailed or two-tailed.
O One-tailed
O Two-tailed
Step 2: Enter the test statistic.
(Round to 3 decimal places.)
Step 3: Shade the area represented by
the p-value.
Step 4: Enter the p-value.
(Round to 3 decimal places.)
A
02+
01+
(d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made
in the school's reports.
O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough
evidence to reject the claim that 39% of students will find a match their first time using the site.
Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not
enough evidence to reject the claim that 39% of students will find a match their first time using the site.
Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence
to reject the claim that 39% of students will find a match their first time using the site.
O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough
evidence to reject the claim that 39% of students will find a match their first time using the site.
Transcribed Image Text:Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p-value. Step 4: Enter the p-value. (Round to 3 decimal places.) A 02+ 01+ (d) Based on your answer to part (c), choose what can be concluded, at the 0.10 level of significance, about the claim made in the school's reports. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 39% of students will find a match their first time using the site. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 39% of students will find a match their first time using the site. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 39% of students will find a match their first time using the site. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 39% of students will find a match their first time using the site.
At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 39% of students will find
a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 160 students who visited the site
looking for a roommate. Of the students surveyed, 54 said they found a match their first time using the site.
Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that the
proportion, p, of all students who will find a match their first time using the site is 39%.
(a) State the null hypothesis H, and the alternative hypothesis H₁ that you would use for the test.
Ho:
H₁:0
р
0<0
0<0
□□ 0=0
(b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One standard is that np≥ 10
and (1-p) ≥10 under the assumption that the null hypothesis is true.) Here is the sample size and p is the population proportion you are testing.
np=0
n(1-p) = ||
(c) Perform a Z-test and find the p-value.
Here is some information to help you with your Z-test.
p-p
⚫ The value of the test statistic is given by
p(1-p)
n
• The p-value is two times the area under the curve to the left of the value of the test statistic.
Transcribed Image Text:At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 39% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 160 students who visited the site looking for a roommate. Of the students surveyed, 54 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that the proportion, p, of all students who will find a match their first time using the site is 39%. (a) State the null hypothesis H, and the alternative hypothesis H₁ that you would use for the test. Ho: H₁:0 р 0<0 0<0 □□ 0=0 (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One standard is that np≥ 10 and (1-p) ≥10 under the assumption that the null hypothesis is true.) Here is the sample size and p is the population proportion you are testing. np=0 n(1-p) = || (c) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. p-p ⚫ The value of the test statistic is given by p(1-p) n • The p-value is two times the area under the curve to the left of the value of the test statistic.
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