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At a mini-golf course, 20 friends each take 5 shots to try and get a hole-in-one. The results are shown in the probability distribution below. Complete the table. Number of Holes-in-one Frequency 2 1 Probability A B CDEF 2. 3. 2. 5.

At a mini-golf course, 20 friends each take 5 shots to try and get a hole-in-one. The results are shown in the probability distribution below. Complete the table. Number of Holes-in-one Frequency 2 1 Probability A B CDEF 2. 3. 2. 5.

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Mini-Golf Probability Distribution** At a mini-golf course, 20 friends each take 5 shots to try and get a hole-in-one. The results are shown in the probability distribution below. Complete the table. | Number of Holes-in-one | 0 | 1 | 2 | 3 | 4 | 5 | |------------------------|---|---|---|---|---|---| | Frequency | 2 | 6 | 5 | 4 | 2 | 1 | | Probability | A | B | C | D | E | F | **Question:** Fill in the probabilities below: A = ( ) B = ( ) C = ( ) D = ( ) E = ( ) F = ( ) **Options Provided:** - 3/10 - 1/20 - 1/4 - 1/10 - 1/5 - 1/2 **Explanation:** To determine each probability, divide the frequency of each number of holes-in-one by the total number of friends (20). The table needs to be filled as follows: A (0 holes-in-one) = Frequency 2 / Total 20 = 2/20 = 1/10 B (1 hole-in-one) = Frequency 6 / Total 20 = 6/20 = 3/10 C (2 holes-in-one) = Frequency 5 / Total 20 = 5/20 = 1/4 D (3 holes-in-one) = Frequency 4 / Total 20 = 4/20 = 1/5 E (4 holes-in-one) = Frequency 2 / Total 20 = 2/20 = 1/10 F (5 holes-in-one) = Frequency 1 / Total 20 = 1/20 So, the filled table will be: A = 1/10 B = 3/10 C = 1/4 D = 1/5 E = 1/10 F = 1/20
Transcribed Image Text:**Mini-Golf Probability Distribution** At a mini-golf course, 20 friends each take 5 shots to try and get a hole-in-one. The results are shown in the probability distribution below. Complete the table. | Number of Holes-in-one | 0 | 1 | 2 | 3 | 4 | 5 | |------------------------|---|---|---|---|---|---| | Frequency | 2 | 6 | 5 | 4 | 2 | 1 | | Probability | A | B | C | D | E | F | **Question:** Fill in the probabilities below: A = ( ) B = ( ) C = ( ) D = ( ) E = ( ) F = ( ) **Options Provided:** - 3/10 - 1/20 - 1/4 - 1/10 - 1/5 - 1/2 **Explanation:** To determine each probability, divide the frequency of each number of holes-in-one by the total number of friends (20). The table needs to be filled as follows: A (0 holes-in-one) = Frequency 2 / Total 20 = 2/20 = 1/10 B (1 hole-in-one) = Frequency 6 / Total 20 = 6/20 = 3/10 C (2 holes-in-one) = Frequency 5 / Total 20 = 5/20 = 1/4 D (3 holes-in-one) = Frequency 4 / Total 20 = 4/20 = 1/5 E (4 holes-in-one) = Frequency 2 / Total 20 = 2/20 = 1/10 F (5 holes-in-one) = Frequency 1 / Total 20 = 1/20 So, the filled table will be: A = 1/10 B = 3/10 C = 1/4 D = 1/5 E = 1/10 F = 1/20
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