At a distance of 5.20 m from a siren, the sound intensity is 4.07 x 102W/m?. Assuming that the siren radiates sound uniformly in all directions, find the total power radiated. Number Units

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

At a distance of 5.20 m from a siren, the sound intensity is \(4.07 \times 10^{-2} \, \text{W/m}^2\). Assuming that the siren radiates sound uniformly in all directions, find the total power radiated.

**Solution:**

To find the total power radiated by the siren, we can use the formula for sound intensity:

\[ I = \frac{P}{A} \]

where \( I \) is the sound intensity, \( P \) is the power, and \( A \) is the area over which the power is distributed. For a source radiating uniformly in all directions, the area \( A \) can be modeled as the surface area of a sphere:

\[ A = 4\pi r^2 \]

Given:
- Sound intensity \( I = 4.07 \times 10^{-2} \, \text{W/m}^2 \)
- Distance \( r = 5.20 \, \text{m} \)

Substitute the values into the equations to find the power \( P \):

\[ A = 4\pi (5.20)^2 \]
\[ P = I \times A \]

- Calculate \( A \).
- Multiply by \( I \) to find \( P \).

**Input Fields:**

- Number: [Input box for calculated power]
- Units: [Dropdown for selecting units, typically Watts (W)]
Transcribed Image Text:**Problem Statement:** At a distance of 5.20 m from a siren, the sound intensity is \(4.07 \times 10^{-2} \, \text{W/m}^2\). Assuming that the siren radiates sound uniformly in all directions, find the total power radiated. **Solution:** To find the total power radiated by the siren, we can use the formula for sound intensity: \[ I = \frac{P}{A} \] where \( I \) is the sound intensity, \( P \) is the power, and \( A \) is the area over which the power is distributed. For a source radiating uniformly in all directions, the area \( A \) can be modeled as the surface area of a sphere: \[ A = 4\pi r^2 \] Given: - Sound intensity \( I = 4.07 \times 10^{-2} \, \text{W/m}^2 \) - Distance \( r = 5.20 \, \text{m} \) Substitute the values into the equations to find the power \( P \): \[ A = 4\pi (5.20)^2 \] \[ P = I \times A \] - Calculate \( A \). - Multiply by \( I \) to find \( P \). **Input Fields:** - Number: [Input box for calculated power] - Units: [Dropdown for selecting units, typically Watts (W)]
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