At a certain temperature, the equilibrium constant K for the following reaction is 1.3: NO₂(g) + CO(g) →NO(g) + CO₂(g) Use this information to complete the following table. Suppose a 45. L reaction vessel is filled with 1.1 mol of NO and 1.1 mol of CO2. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. NO(g) + CO2(9) NO ₂(g) + CO (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO₂(9)+2CO(g) 2NO(g)+2CO₂(g) O There will be very little NO₂ and CO. O There will be very little NO and CO2₂. O Neither of the above is true. K = K = 0

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At a certain temperature, the equilibrium constant K for the following reaction is 1.3:
NO₂(g) + CO(g) NO(g) + CO₂(g)
Use this information to complete the following table.
Suppose a 45. L reaction vessel is filled with 1.1 mol of NO and
1.1 mol of CO₂. What can you say about the composition of the
mixture in the vessel at equilibrium?
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
NO (9)+ CO₂(9)
NO ₂(g) +CO (9)
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
2 NO₂(9)+2CO (g) U
2 NO(g) + 2CO₂(9)
There will be very little NO₂ and CO.
There will be very little NO and CO₂.
ONeither of the above is true.
K = 0
K = 0
Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 1.3: NO₂(g) + CO(g) NO(g) + CO₂(g) Use this information to complete the following table. Suppose a 45. L reaction vessel is filled with 1.1 mol of NO and 1.1 mol of CO₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. NO (9)+ CO₂(9) NO ₂(g) +CO (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO₂(9)+2CO (g) U 2 NO(g) + 2CO₂(9) There will be very little NO₂ and CO. There will be very little NO and CO₂. ONeither of the above is true. K = 0 K = 0
Expert Solution
Step 1: Equilibrium constant expression for the given reaction

Answer:

Given reaction:

NO subscript 2 left parenthesis straight g right parenthesis plus CO left parenthesis straight g right parenthesis rightwards harpoon over leftwards harpoon NO left parenthesis straight g right parenthesis plus CO subscript 2 left parenthesis straight g right parenthesis

equilibrium constant expression for the above reaction is:

straight K equals fraction numerator left square bracket NO right square bracket left square bracket CO subscript 2 right square bracket over denominator left square bracket NO subscript 2 right square bracket left square bracket CO right square bracket end fraction space space space space space space space space...... equation left parenthesis 1 right parenthesis

Here value of K is 1.3

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