Assuming that the concentration of NaOH is 0.1M Analysis of acetic acid   Trial   1 2 Volume of acetic acid 10ml 10ml Initial buret reading 1ml 6.6ml Final buret reading 29.9ml              35.1ml Volume of NaOH used 28.9 28.5 Mass (g) acetic acid     Average   1. Show the complete solution for the analysis of acetic acid (Trial 1 only) 2. Calculate the average mass of acetic acid.

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Q: 1. Does your molarity of acetic acid agree with the percent of acetic acid present in the sample?…

A: As per the rules, only the first question can be answered.

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A: According to law of equivalence ,  M1V1 = M2V2 Where M1 and M2 are initial and final concentration…

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A: Concentration of NaOH for trials 1 and 2 = 0.0500 MVolume of NaOH for trial 1 = 30.5 mLVolume of…

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A: Given: The compound is lead sulfate i.e. PbSO4. And the volume of solution = 175 mL = 0.175 L…

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Q: Date: Section: Data Report Sheet: Analysis of an Unknown Chloride Unknown # Molarity of Standard…

A: Most of your calculations are right, except for some calculations in Trial II. All calculations for…

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A: Mass of KHP = 2.02 g for trial 1, 2.05 g for trial 2, 1.99 g for trial 3Initial volume of NaOH =…

Q: Concentration 6.5x10^-5 M Submit Answer Try Another Version 2 item attempts remaining Not Submitted

A: For getting just precipitate we need to equal  KIP=Ksp Ip is Ionic product.

Q: KHP (aq)+NaOH (aq)-->NaKHP (aq)+H2O(l)   Trial  Vi (mL) Vf (mL) 1 36.19 48.56 2     3       A…

A: According to the chemical equation, the number of moles of KHP react with NaOH are equal.

Q: MISSED THIS? Read Section 5.7 (Pages 185-191); Watch KCV 5.5, IWE 5.9. Enter balanced complete ionic…

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A: Reaction of KHP with NaOH: KHP (aq)+ NaOH (aq)→KNa(aq)+H2O(l) NaOH and KHP reacts in 1: 1…

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Q: Student Name: Data Trial 1 Trial 2 Mass of flask, rubber band, and foil (g) 143.2 92 143.44 136.91…

A: Please have a look on the solution below:

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Q: Standardization of NaOH Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 0.785 0. l690g 0.8239 Mass of KHP…

A: The mass of KHP used in trial 1, trial 2 and trial 3 is 0.785 g, 0.690 g and 0.823 g, respectively.…

Q: MasteringChemistry…

A: Hi there, as there are multiple questions posted. We are answering the first question(question…

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A: Answer :-  a) Mass percent of CH3CH2OH = 34.0%  b) Mole fraction of CH3CH2OH = 0.167…

Q: HC2H3O2 (aq) + NaOH (aq) ----> NaC2H3O2 (aq) + H2O(l) Trial  Vi (mL) Vf (mL) 1 2.25 15.76 2     3…

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Q: A student prepares a 1.2 mM aqueous solution of benzoic acid (C,H,CO,H). Calculate the fraction of…

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Q: balanced molecular equation (ME)  write the balanced complete ionic equation (CIE)  and write the…

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A: The data given is,

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Q: Chemistry Find the molarity of NaOH, net volume, and average molarity using the data given:…

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Q: Acid Base Titrations Given the information below, calculate the acid concentration: show work and…

A: Given that ,  Acid is HCl and base is NaOH  Concentration of NaOH (M1) = 0.10 M Initial Buret…