**Question:**What volume of a 0.43 M ZnCl₂ solution contains 2.52 g of ZnCl₂? \( M_W \, \text{ZnCl}_2 = 136.29 \, \text{g/mol} \).**Options:**- A. 0.0080 L- B. 5.9 L- C. 23 L- D. 43 mL- E. 5.9 mL**Explanation:**To solve the question, perform the following steps:1. **Calculate the moles of ZnCl₂:** \[ \text{moles of ZnCl}_2 = \frac{2.52 \, \text{g}}{136.29 \, \text{g/mol}} \]2. **Use the molarity to find the volume:** \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] Rearrange to solve for volume: \[ \text{Volume} = \frac{\text{moles of ZnCl}_2}{0.43 \, \text{M}} \] 3. **Match your calculated volume with the given options.**This question requires knowledge of molarity, molar mass, and the conversion between grams and moles to determine the correct volume.

We know that Molarity = number of moles of solute / volume of the solution in L Number of moles =…

Answered: What volume of a 0.43 M ZnCl2 solution…

What volume of a 0.43 M ZnCl2 solution contains 2.52 g of ZnCl2? Mw ZnCl2 = 136.29 g/mol. %3D OA 0.0080OL O B. 5.9 L OC 23 L OD. 43 mL O E. 5.9 mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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