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What volume of a 0.43 M ZnCl2 solution contains 2.52 g of ZnCl2? Mw ZnCl2 = 136.29 g/mol. %3D OA 0.0080OL O B. 5.9 L OC 23 L OD. 43 mL O E. 5.9 mL

What volume of a 0.43 M ZnCl2 solution contains 2.52 g of ZnCl2? Mw ZnCl2 = 136.29 g/mol. %3D OA 0.0080OL O B. 5.9 L OC 23 L OD. 43 mL O E. 5.9 mL

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question:** What volume of a 0.43 M ZnCl₂ solution contains 2.52 g of ZnCl₂? \( M_W \, \text{ZnCl}_2 = 136.29 \, \text{g/mol} \). **Options:** - A. 0.0080 L - B. 5.9 L - C. 23 L - D. 43 mL - E. 5.9 mL **Explanation:** To solve the question, perform the following steps: 1. **Calculate the moles of ZnCl₂:** \[ \text{moles of ZnCl}_2 = \frac{2.52 \, \text{g}}{136.29 \, \text{g/mol}} \] 2. **Use the molarity to find the volume:** \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] Rearrange to solve for volume: \[ \text{Volume} = \frac{\text{moles of ZnCl}_2}{0.43 \, \text{M}} \] 3. **Match your calculated volume with the given options.** This question requires knowledge of molarity, molar mass, and the conversion between grams and moles to determine the correct volume.
Transcribed Image Text:**Question:** What volume of a 0.43 M ZnCl₂ solution contains 2.52 g of ZnCl₂? \( M_W \, \text{ZnCl}_2 = 136.29 \, \text{g/mol} \). **Options:** - A. 0.0080 L - B. 5.9 L - C. 23 L - D. 43 mL - E. 5.9 mL **Explanation:** To solve the question, perform the following steps: 1. **Calculate the moles of ZnCl₂:** \[ \text{moles of ZnCl}_2 = \frac{2.52 \, \text{g}}{136.29 \, \text{g/mol}} \] 2. **Use the molarity to find the volume:** \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] Rearrange to solve for volume: \[ \text{Volume} = \frac{\text{moles of ZnCl}_2}{0.43 \, \text{M}} \] 3. **Match your calculated volume with the given options.** This question requires knowledge of molarity, molar mass, and the conversion between grams and moles to determine the correct volume.
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