.com/ilmn/takeAssignment/takeCovalentActivity.do?locator=assignment-takeWhat is the molarity of the solution prepared by diluting 20.0 mL of 0.492 M Mg(NO3)2 solution to each of the followingfinal volumes?a. 40.0 mLMolarityb. 125 mLMolarity =c. 1.10 LMolarity =d. 375 mLMolarity =D=Submit AnswerMMMMRetry Entire Group1 more group attempt remainingPreviousEmail InstructorNextSave a om/ilmn/takeAssignment/takeCovalentActivity.do?locator=assignment-takeHow many milliliters of 0.250 M HCl would be needed to react exactly with 12.0 g of solid NaHCO3?NaHCO3(s) + HCl(aq) → NaCl(aq) + CO₂(g) + H₂O(l)mLSubmit AnswerrogressRetry Entire Group 1 more group attempt remaining

As we know , Moles the solute remains same on dilution but volume of the solution increases.…

om/ilmn/takeAssignment/takeCovalentActivity.do?locator-assignment-take What is the molarity of the solution prepared by diluting 20.0 mL of 0.492 M Mg(NO3)2 solution to each of the following final volumes? a. 40.0 mL Molarity = b. 125 mL Molarity = c. 1.10 L Molarity = d. 375 mL Molarity = Submit Answer M M M M Retry Entire Group 1 more group attempt remaining

om/ilmn/takeAssignment/takeCovalentActivity.do?locator-assignment-take What is the molarity of the solution prepared by diluting 20.0 mL of 0.492 M Mg(NO3)2 solution to each of the following final volumes? a. 40.0 mL Molarity = b. 125 mL Molarity = c. 1.10 L Molarity = d. 375 mL Molarity = Submit Answer M M M M Retry Entire Group 1 more group attempt remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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5. You will also make other concentrations of solutions. If the concentration is to be less than a mole, reduce the mass of the substance accordingly. If the concentration is to be greater than 1M, increase BIOL 1406 the mass added or reduce the volume of water accordingly. Use this formula: Molarity = moles/liter. Example: Make a .5M solution of HCI Name: H = 1.008 Daltons CI = 35.45 Daltons Total = 36.46 Daltons = 36.46 grams .5M = X moles/1 liter .5M * 1 liter = X moles Date Number of moles = .5 .5 * 36.46 = 18.23 grams Add 500 mLs water to 1L volumetric flask, add the 18.23 grams HCI to the water, swirl to dissolve, then add water until it reaches the 1L or 1,000 mL mark. Answer the following questions: 1. How many mL should I use to make a 1M solution of MgBr2? ¶ 2. What is the mass of a mole of NH3? 3. How much CaCO3 should I use to make a 2M solution? 4. How much CaCO3 should I use to make a .25M solution? 5. What are the steps to make a 1M solution of NH3 - give the steps and…
A chemical reaction has the equation 2NaCI (aq) + F2 (g) -› 2NaF (s) + Cl 2(g). What type of reaction occurs between NaCl and F2»? A. Synthesis B. Decomposition C. Double displacement © D. Single displacement
The U.S. standard for arsenate in drinking water requires thatpublic water supplies must contain no greater than 10 partsper billion (ppb) arsenic. If this arsenic is present as arsenate,AsO43-, what mass of sodium arsenate would be present ina 1.00-L sample of drinking water that just meets the standard?Parts per billion is defined on a mass basis asppb =g soluteg solution * 109
3. Your lab space has a 100. mL bottle of 2.0 M LiAlH4. You need to make 50. mL of 0.10M LiAlH4. What volume of the original bottle should be diluted?
A chemist was asked to determine the molecular weight of Compound J. They created a solution with 20 percentage w/w concentration from solid Compound J, with a density of 1.40 g/mL. From this solution, a 10 μL aliquot was taken and mixed with 190μL of reagent and water. This was then analyzed and had 5.0 e-4 M compound J. What is the concentration in molarity of the 20% w/w solution? How do you determine the molecular weight of said compound?
A researcher wants to determine the concentration of beta-carotene in carrots. She obtains a 0.558 M stock solution of beta-carotene and creates Dilution A by transferring 15.00 mL of stock solution into a new container and diluting it with solvent to a final volume of 90.00 mL. She creates Dilution B by transferring 53.00 mL of stock solution into a new container and diluting it with solvent to a final volume of 80.00 mL. She creates Dilution C by transferring 2.00 mL of Dilution B into a new container and diluting it with solvent to a final volume of 15.00 mL. What is the concentration in mM of Dilution C? use one decimal place
You are given a stock concentration of ADH. The molecular weight of ADH is 35,000 g/mol. a. What is the molarity of a 54 mg/ml stock solution of ADH? b. you dilute an ADH stock. The concentration is listed below. What is the molarity of a solution made from 78ul of 0 mM stock solution in 17 ml final volume?
A 2.00 mL aliquot of reagent grade HCl was diluted to 250.0 mL. The diluted solution was standardized using sodium carbonate, and the concentration of the prepared solution was determined to be 0.09606 M HCl. What is the concentration of reagent HCl (in %w/w)? Note: the specific gravity of the reagent HCl was 1.18 g/mL.
13. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into 500-mL volumetric flask and diluting to volume. What is the molar concentratio of NaCl in solutions A, B and C?
A 20.0 g of Na2CO3 (106.0 g/mol) is dissolved in 75.0 mL of 0.300 M NaOH. What is the molarity of the Na* in the resulting solution? Assume the volume does not change. O a. 1.41 M O b. 5.63 M O c. 1.55 M O d. 2.82 M O e. 5.33 M
How would you prepare: a. 5.00 L of 1.50 M KMnO4 from solid reagent. b. 400.0 mL of a solution that is 0.0500 M I- starting with MgI2. c. 4.00 L of 0.175 M HCIO4, starting with an 8.00 M solution of the reagent.
1. A 0.10 M HNO3 solution will be prepared from concentrated HNO3. a. Using the method outlined in Experiment 5, determine the concentration of a stock bottle of concentrated nitric acid. [density = 1.42 g/mL; 70% by mass HNO3] b. Calculate the volume of concentrated NO3 needed to prepare 500 mL of a 0.10 %3D M solution.