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Assuming a surface temperature of 60 °F and a linear geothermal gradient of 30 °C/km, what is the temperature (in °C) at a depth of 6562 ft?

Assuming a surface temperature of 60 °F and a linear geothermal gradient of 30 °C/km, what is the temperature (in °C) at a depth of 6562 ft?

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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@ (b) (c) Assuming a surface temperature of 60 °F and a linear geothermal gradient of 30 °C/km, what is the temperature (in °C) at a depth of 6562 ft? Answer: 6562 ft = 2 km; 60 °F - 15.6 °C, plus 30 °C/km * 2km = 75.6 °C wwwww Assuming that, in the depth interval of 1,000-1,500m, the natural geothermal gradient is convection-dominated instead of linear, with perfect temperature mixing, what is the temperature (in °C) at 1,250m, still starting with a linear geothermal gradient of 30 °C/km from 60 °F at the surface? Answer: the geothermal gradient will be flat within the interval, with the same tempera throughout, equal to 15.6 °C +30 °C/km * 1km = 45.6 °C Assuming a geothermal well drilled at this location, producing 250 kg/s of pure water (Cp = 4,180 J/kg.s) at 65 °C at the wellhead, what would be the electric power output of an ORC power plant installed at the wellhead, extracting 20 °C from the geofluid with an efficiency of 10%? Answer: Q = m* cp * deltaT * n = 250 kg/s * 4,180 J/kg.s* 20 K * 0.1= 2 MW
Transcribed Image Text:@ (b) (c) Assuming a surface temperature of 60 °F and a linear geothermal gradient of 30 °C/km, what is the temperature (in °C) at a depth of 6562 ft? Answer: 6562 ft = 2 km; 60 °F - 15.6 °C, plus 30 °C/km * 2km = 75.6 °C wwwww Assuming that, in the depth interval of 1,000-1,500m, the natural geothermal gradient is convection-dominated instead of linear, with perfect temperature mixing, what is the temperature (in °C) at 1,250m, still starting with a linear geothermal gradient of 30 °C/km from 60 °F at the surface? Answer: the geothermal gradient will be flat within the interval, with the same tempera throughout, equal to 15.6 °C +30 °C/km * 1km = 45.6 °C Assuming a geothermal well drilled at this location, producing 250 kg/s of pure water (Cp = 4,180 J/kg.s) at 65 °C at the wellhead, what would be the electric power output of an ORC power plant installed at the wellhead, extracting 20 °C from the geofluid with an efficiency of 10%? Answer: Q = m* cp * deltaT * n = 250 kg/s * 4,180 J/kg.s* 20 K * 0.1= 2 MW
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