temperature with respect to the geopotential height at pressure level pi is given by -Ry/g Po To =- Z = P1 Jouol tomnerature and pressure, respectively.
temperature with respect to the geopotential height at pressure level pi is given by -Ry/g Po To =- Z = P1 Jouol tomnerature and pressure, respectively.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Q1.17
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Calculate the 1000 to 500 hPa thickness for a constant lapse rate atmosphere with y=6.5 K km^(-1) and T_o= 273 K.
![1.14. Show that a homogeneous
bundary.
ture To = 273 K and surface pressure 1000 hPa. (Use the ideal
hydrostatic balance.)
1.15. For the conditions of the previous problem, compute the variation of u
temperature with respect to height.
1.16. Show that in an atmosphere with uniform lapse rate (where y =-
the geopotential height at pressure level pi is given by
a finite height that depends only on the temperature at
gas law and
-dT /dz)
-Ry/g
Po
To
Z = -
where To and po are the sea-level temperature and pressure, respectively.
1.17. Calculate the 1000 to 500 hPa thickness for a constant lapse rate atmo-
sphere with y = 6.5 K km- and To
the results in Problem 1.12.
273 K. Compare your results with
%3D
1.18. Derive an expression for the variation in density with respect to height in a
constant lapse rate atmosphere.
1.19. Derive an expression for the altitude variation in the pressure change &p
that occurs when an atmosphere with a constant lapse rate is subjected
to a height-independent temperature change 8T while the surface pressure
remains constant. At what height is the magnitude of the pressure change a
maximum if the lapse rate is 6.5 K km-', To = 300, and 8T
= 2 K?
MATLAB Exercises
M1.1. This exercise investigates the role of the curvature terms for high-latitu
constant angular momentum trajectories.
(a) Run the coriolis.m script with the following initial conditions: init
latitude 60°, initial velocity u = 0, v = 40 ms-, run time = 5 days. Co
the
appearance of the trajectories for the case with the curvatu
pare
terms included and the case with the curvature terms neglected. Qu
itatively explain the difference that you observe. Why is the trajecto
not a closed circle as described in Eq. (1.15) of the text? [Hint: Consic
the separate effects of the term proportional to tan o and of the spherie
geometry.]
(b) Run coriolis.m with latitude 60°, u = 0, v = 80 m/s w
from case (a)? By varying the run time sn](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F688dd0d6-23e9-4822-a053-95219c75dd48%2Fe3af2c27-8e45-459d-b5cd-623cff7dd910%2Feahte6f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.14. Show that a homogeneous
bundary.
ture To = 273 K and surface pressure 1000 hPa. (Use the ideal
hydrostatic balance.)
1.15. For the conditions of the previous problem, compute the variation of u
temperature with respect to height.
1.16. Show that in an atmosphere with uniform lapse rate (where y =-
the geopotential height at pressure level pi is given by
a finite height that depends only on the temperature at
gas law and
-dT /dz)
-Ry/g
Po
To
Z = -
where To and po are the sea-level temperature and pressure, respectively.
1.17. Calculate the 1000 to 500 hPa thickness for a constant lapse rate atmo-
sphere with y = 6.5 K km- and To
the results in Problem 1.12.
273 K. Compare your results with
%3D
1.18. Derive an expression for the variation in density with respect to height in a
constant lapse rate atmosphere.
1.19. Derive an expression for the altitude variation in the pressure change &p
that occurs when an atmosphere with a constant lapse rate is subjected
to a height-independent temperature change 8T while the surface pressure
remains constant. At what height is the magnitude of the pressure change a
maximum if the lapse rate is 6.5 K km-', To = 300, and 8T
= 2 K?
MATLAB Exercises
M1.1. This exercise investigates the role of the curvature terms for high-latitu
constant angular momentum trajectories.
(a) Run the coriolis.m script with the following initial conditions: init
latitude 60°, initial velocity u = 0, v = 40 ms-, run time = 5 days. Co
the
appearance of the trajectories for the case with the curvatu
pare
terms included and the case with the curvature terms neglected. Qu
itatively explain the difference that you observe. Why is the trajecto
not a closed circle as described in Eq. (1.15) of the text? [Hint: Consic
the separate effects of the term proportional to tan o and of the spherie
geometry.]
(b) Run coriolis.m with latitude 60°, u = 0, v = 80 m/s w
from case (a)? By varying the run time sn
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