Assuming a secondary system consisting of step down distribution transformer (DT) with line to line input output voltages 20KV - 380V respectively (220V line-neutral). Two low voltage electric motors M1 (single phase with S1=15KVA and PF1=0.8 lag) and M2 (three phase- balanced with S2=30KVA and PF2=0.8 lag) are fed directly from the secondary main and located at distances from the DT as shown in the figure. Assuming that the secondary feeder main has R=0.50/km and X=0.20/km.

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Assuming a secondary system consisting of step down distribution transformer (DT) with line to line input output voltages 20KV - 380V
respectively (220V line-neutral). Two low voltage electric motors M1 (single phase with S1=15KVA and PF1=0.8 lag) and M2 (three phase-
balanced with S2=30KVA and PF2=0.8 lag) are fed directly from the secondary main and located at distances from the DT as shown in the
figure. Assuming that the secondary feeder main has R=0.50/km and X=0.20/km.
TRANSFORMER
Primary 20KV-220/380V
F1
Secondary main
1
3
LV.CB
S1
Motor.1
pf=0.8
S2
(Motor.2
pf=0.8
AB=200m
BC=200m
A
в
If Motors 1 and 2 are ON, the maximum percentage voltage drop %VD and the total copper losses Pis of the feeder main will be:
Select one:
O a. %VD = 9.74% & PLS = 2369 Watt
O b. %VD = 10.74% & PLS = 2789 Watt
O c. %VD = 9.74% & PLS = 2569 Watt
O d. %VD = 10.74% & PLS =2169 Watt
Oe.
%VD = 9.74% & PLS = 2469 Watt
O f. None of these
Transcribed Image Text:Assuming a secondary system consisting of step down distribution transformer (DT) with line to line input output voltages 20KV - 380V respectively (220V line-neutral). Two low voltage electric motors M1 (single phase with S1=15KVA and PF1=0.8 lag) and M2 (three phase- balanced with S2=30KVA and PF2=0.8 lag) are fed directly from the secondary main and located at distances from the DT as shown in the figure. Assuming that the secondary feeder main has R=0.50/km and X=0.20/km. TRANSFORMER Primary 20KV-220/380V F1 Secondary main 1 3 LV.CB S1 Motor.1 pf=0.8 S2 (Motor.2 pf=0.8 AB=200m BC=200m A в If Motors 1 and 2 are ON, the maximum percentage voltage drop %VD and the total copper losses Pis of the feeder main will be: Select one: O a. %VD = 9.74% & PLS = 2369 Watt O b. %VD = 10.74% & PLS = 2789 Watt O c. %VD = 9.74% & PLS = 2569 Watt O d. %VD = 10.74% & PLS =2169 Watt Oe. %VD = 9.74% & PLS = 2469 Watt O f. None of these
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