Assuming 100% dissociation, calculate the freezing point (T;) and boiling point (T,) of 1.59 m K¸PO,(aq). Colligative constants can be found in the chempendix. T = -8.87 °C Incorrect 100.73 °C Incorrect
Assuming 100% dissociation, calculate the freezing point (T;) and boiling point (T,) of 1.59 m K¸PO,(aq). Colligative constants can be found in the chempendix. T = -8.87 °C Incorrect 100.73 °C Incorrect
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Assuming 100% dissociation, calculate the freezing point (T;) and boiling point (T,) of 1.59 m K,PO,(aq).
Colligative constants can be found in the chempendix.
Tf =
-8.87
°C
Incorrect
Th =
100.73
°C
Incorrect
Transcribed Image Text:amacmillan
learning
Colligative Constants
Chempendix
Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
Physical Constants
Kf value* Normal freezing K, value Normal boiling
(°C/ m)
Acids and Bases
Solvent
Formula
(°C/ m)
point (°C)
point (°C)
H20
C 6 H6
cyclohexane C 6 H 12
C2H60 1.99
water
1.86
0.00
0.512
100.00
Activity Coefficients
benzene
5.12
5.49
2.53
80.1
Activity Series
20.8
6.59
2.92
80.7
ethanol
-117.3
1.22
78.4
Amino Acids
carbon
|CCI 4
29.8
-22.9
5.03
76.8
tetrachloride
Boiling Points
camphor
С 10 Н 16 0 37.8
176
Bond Energies
Bond Lengths
Codons
*When using positive Kf values, assume that ATf is the absolute value of the change in temperature. If you would prefer to define ATfas "final minus initial"
temperature, then ATf will be negative and so you must use negative Kf values. Either way, the freezing point of the solution should be lower than that of
Colligative Constants
the pure solvent.
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