: Assume we can represent a non-negative integer using a stack where each digit is stored as one item on the stack. For example, the code below stores the values 385 as [3, 8, 5] with the least significant digit (i.e. 5) on the top of the stack: Stack nusi new Stack<>(); num1.push(3); num1.push(8); numi.push(5); //num1 stores the value 385 Write a method that adds two numbers represented as described above. The method should return a stack containing the sum. Use this header: Stack add(Stack num1, Stack num2) Note that: 1. the number of digits in the two arguments is not necessarily the same, 2. the number 0 can be represented as a stack with a single element [0] or as an empty stack. Here are a few samples: Intended Operation num1 as a stack num2 as a stack returned result as a stack [3,8, 5] [3.8, 5] [3,8, 5] 385+0 385 Either [] or [0] [3.8, 5] 385+97 482 [9,7] [8,9, 7] [4, 8, 2) [1.2, 8, 2] 385+897 = 1282 Here is an example for adding 385 + 97: Stack numi - new Stack<>(); numt.push(3); numl.push(8); numl.push(5); //num1 [3,8,5], 1.e. 385 Stack num2 new Stack<>(); num2.push(9); num2.push(7); Inum2- [9, 7], 1.e. 97 Stack result add (num1, num2); System.out.println(result); 1/prints [4,8,2], i.e. 482

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Question
: Assume we can represent a non-negative integer using a stack where each digit is stored
as one item on the stack. For example, the code below stores the values 385 as [3, 8, 5] with the
least significant digit (i.e. 5) on the top of the stack:
Stack<Integer> nus1 new Stack<>();
numl.push(3); num1.push(8); num1.push(5); //num1 stores the value 385
Write a method that adds two numbers represented as described above. The method should return
a stack containing the sum. Use this header:
Stack<Integer> add(Stack<Integer> numi, Stack<Integer> num2)
Note that:
1. the number of digits in the two arguments is not necessarily the same,
2. the number 0 can be represented as a stack with a single element [0] or as an empty stack.
Here are a few samples:
Intended Operation
num1 as a stack
num2 as a stack
returned result as a stack
[3,8, 5]
[3.8,5]
[3,8, 5]
Either [] or [0] [3,8, 5]
[9,7]
(8,9,7]
385+0 385
%3D
385+97 482
[4,8, 2)
%3D
385+897 1282
[1.2, 8, 2)
Here is an example for adding 385 +97:
Stack<Integer> numi - new Stack<>();
numi.push(3); num1.push(8); numl.push(5); //num1-
[3,8,5], 1.e. 385
Stack<Integer> num2 new Stack<>();
num2.push(9); num2.push(7);
I {num2- [9, 7], 1.e. 97
Stack<Integer> result add (num1, num2);
System.out.println(result);
/prints [4,8,2], i.e. 482
Transcribed Image Text:: Assume we can represent a non-negative integer using a stack where each digit is stored as one item on the stack. For example, the code below stores the values 385 as [3, 8, 5] with the least significant digit (i.e. 5) on the top of the stack: Stack<Integer> nus1 new Stack<>(); numl.push(3); num1.push(8); num1.push(5); //num1 stores the value 385 Write a method that adds two numbers represented as described above. The method should return a stack containing the sum. Use this header: Stack<Integer> add(Stack<Integer> numi, Stack<Integer> num2) Note that: 1. the number of digits in the two arguments is not necessarily the same, 2. the number 0 can be represented as a stack with a single element [0] or as an empty stack. Here are a few samples: Intended Operation num1 as a stack num2 as a stack returned result as a stack [3,8, 5] [3.8,5] [3,8, 5] Either [] or [0] [3,8, 5] [9,7] (8,9,7] 385+0 385 %3D 385+97 482 [4,8, 2) %3D 385+897 1282 [1.2, 8, 2) Here is an example for adding 385 +97: Stack<Integer> numi - new Stack<>(); numi.push(3); num1.push(8); numl.push(5); //num1- [3,8,5], 1.e. 385 Stack<Integer> num2 new Stack<>(); num2.push(9); num2.push(7); I {num2- [9, 7], 1.e. 97 Stack<Integer> result add (num1, num2); System.out.println(result); /prints [4,8,2], i.e. 482
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