0:00 IZVV58Stack s - new Stack();s. push(10);s. push(20);s. push(30);s. push(40);// stack created with elements- 10 20 30 4059606162636465sum(s);66public static void sum(stack s){Integer sum = 0;stack tmp = new Stack();// move the stack to new stack, it will be in reverse orde// simultaneously sum the elementswhile (Is.isEmpty())(tmp.push(s.pop();sum t tmp.peek();6768697071727374sum t= tmp.peek ();7475// move to original stackwhile (Itmp.isEmpty()){s.push(tmp.pop());system.out.println("sum= "+sum.tostring());OUTPUT-10 pushed into stack20 pushed into stack30 pushed into stack40 pushed into stack40 pushed into stack30 pushed into stack20 pushed into stack10 pushed into stack10 pushed into stack20 pushed into stack30 pushed into stack40 pushed into stackSum= 100Sum of 10, 2O, 30, 40 = 100I hope it helps. For any doubt, feel free to ask incomments, and give upvote if u get the answer.

I give the code in java as per your requirement along with code and output screenshot

Stack s- new Stack(); s. push(10); s. push(20); s.push(30); s.push(40); // Stack created with elements- 10 20 30 40 60 61 62 63 64 65 (s)ans 66 67 public static void sum(Stack s){ Integer sum - 0; stack tmp = new Stack(); // move the stack to new stack, it will be in reverse orde // simultaneously sum the elements while (Is.isEmpty())( tmp.push(s.pop()); Sum tap.peek); 70 71 73 74 sum tmp.peek(); 74 75 // move to original stack while (Itmp.isEmpty()){ s. push(tmp.pop(); 76 system.out.printin("Sum= "+sum.tostring()); } OUTPUT- 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack | 40 pushed into stack 30 pushed into stack 20 pushed into stack 10 pushed into stack 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack Sum= 100

Stack s- new Stack(); s. push(10); s. push(20); s.push(30); s.push(40); // Stack created with elements- 10 20 30 40 60 61 62 63 64 65 (s)ans 66 67 public static void sum(Stack s){ Integer sum - 0; stack tmp = new Stack(); // move the stack to new stack, it will be in reverse orde // simultaneously sum the elements while (Is.isEmpty())( tmp.push(s.pop()); Sum tap.peek); 70 71 73 74 sum tmp.peek(); 74 75 // move to original stack while (Itmp.isEmpty()){ s. push(tmp.pop(); 76 system.out.printin("Sum= "+sum.tostring()); } OUTPUT- 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack | 40 pushed into stack 30 pushed into stack 20 pushed into stack 10 pushed into stack 10 pushed into stack 20 pushed into stack 30 pushed into stack 40 pushed into stack Sum= 100

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

0:00 I
ZVV
58
Stack s - new Stack();
s. push(10);
s. push(20);
s. push(30);
s. push(40);
// stack created with elements- 10 20 30 40
59
60
61
62
63
64
65
sum(s);
66
public static void sum(stack s){
Integer sum = 0;
stack tmp = new Stack();
// move the stack to new stack, it will be in reverse orde
// simultaneously sum the elements
while (Is.isEmpty())(
tmp.push(s.pop();
sum t tmp.peek();
67
68
69
70
71
72
73
74
sum t= tmp.peek ();
74
75
// move to original stack
while (Itmp.isEmpty()){
s.push(tmp.pop());
system.out.println("sum= "+sum.tostring());
OUTPUT-
10 pushed into stack
20 pushed into stack
30 pushed into stack
40 pushed into stack
40 pushed into stack
30 pushed into stack
20 pushed into stack
10 pushed into stack
10 pushed into stack
20 pushed into stack
30 pushed into stack
40 pushed into stack
Sum= 100
Sum of 10, 2O, 30, 40 = 100
I hope it helps. For any doubt, feel free to ask in
comments, and give upvote if u get the answer.

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solution for subpart 3
Consider the following statements: stackType<int> stack; int x; Suppose that the input is: 14 53 34 32 13 5 -999 Show what is output by the following segment of code: cin >> x; while (x != -999) { if (x % 2 == 0) { if (!stack.isFullStack()) stack.push(x); } else cout << "x = " << x << endl; cin >> x; } cout << "Stack Elements: "; while (!stack.isEmptyStack()) { cout << " " << stack.top(); stack.pop(); } cout << endl;
Please elaborate on the distinction between the bound and unbounded stack.
solution for subpart 4