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Assume the equilibrium equations below. x-equation: A - BE() + CD = 0 y-equation: Ay - BE() = 0 Moment about point A: BE··6-CD-10 = 0 Use CD from the original diagram. Determine the support reaction in lb at A in the x-direction. (Give the answer t .

Assume the equilibrium equations below. x-equation: A - BE() + CD = 0 y-equation: Ay - BE() = 0 Moment about point A: BE··6-CD-10 = 0 Use CD from the original diagram. Determine the support reaction in lb at A in the x-direction. (Give the answer t .

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Assume the equilibrium equations below. x-equation: \( A_x - BE \cdot \left(\frac{3}{5}\right) + CD = 0 \) y-equation: \( A_y - BE \cdot \left(\frac{4}{5}\right) = 0 \) Moment about point A: \( BE \cdot \frac{3}{5} \cdot 6 - CD \cdot 10 = 0 \) Use CD from the original diagram. Determine the **support reaction in lb at A in the x-direction**. (Give the answer to 0 decimal places.) [Input field for answer]
Transcribed Image Text:Assume the equilibrium equations below. x-equation: \( A_x - BE \cdot \left(\frac{3}{5}\right) + CD = 0 \) y-equation: \( A_y - BE \cdot \left(\frac{4}{5}\right) = 0 \) Moment about point A: \( BE \cdot \frac{3}{5} \cdot 6 - CD \cdot 10 = 0 \) Use CD from the original diagram. Determine the **support reaction in lb at A in the x-direction**. (Give the answer to 0 decimal places.) [Input field for answer]
**2D Particle Equilibrium** In this exercise, you will be determining the tensions in the ropes (shown in blue) and the reactions for the support of the system outlined below. The black vertical bar is rigid, and there is a pin support at point A. One rope connects between points B and E, and the other rope is connected to the vertical bar at C. This second rope then wraps around a simple pulley (shown in red) to hold a weight of 225 lb. **Diagram Explanation:** - The vertical and horizontal distances are marked: - Vertical distance from point B to E is 8 ft. - Vertical distance from point C to E is 12 ft. - Horizontal distance from point A to E is 12 ft. - Horizontal distance from point A to weight of 225 lb is 10 ft, with an additional 6 ft to the end of the black horizontal bar. The system comprises a black vertical bar, blue ropes, and a 225 lb weight suspended via a pulley system. The task is to calculate the tensions within these ropes and the supporting reactions at the pin support at point A.
Transcribed Image Text:**2D Particle Equilibrium** In this exercise, you will be determining the tensions in the ropes (shown in blue) and the reactions for the support of the system outlined below. The black vertical bar is rigid, and there is a pin support at point A. One rope connects between points B and E, and the other rope is connected to the vertical bar at C. This second rope then wraps around a simple pulley (shown in red) to hold a weight of 225 lb. **Diagram Explanation:** - The vertical and horizontal distances are marked: - Vertical distance from point B to E is 8 ft. - Vertical distance from point C to E is 12 ft. - Horizontal distance from point A to E is 12 ft. - Horizontal distance from point A to weight of 225 lb is 10 ft, with an additional 6 ft to the end of the black horizontal bar. The system comprises a black vertical bar, blue ropes, and a 225 lb weight suspended via a pulley system. The task is to calculate the tensions within these ropes and the supporting reactions at the pin support at point A.
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