I got stuck with this problem. Can you help? I fear I didn't identify all the forces required 5. For the structure shown, if h=200 mm, determinethe reactions at A and B.(Answer: RA=519 N12.6° RB 586 N 30°300 mmT250mmс250mm180 Noy.160⁰

h=200mm To find reaction at A and B

Answered: 5. For the structure shown, if h=200…

5. For the structure shown, if h=200 mm, determine the reactions at A and B. Answer: RA= 519 N 12.6° RB-586 N 30° 300 mm 250 mm 250 mm 180 N

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter5: Three-dimensional Equilibrium

Section: Chapter Questions

Problem 5.31P: Calculate the reaction at D for the structure described in Prob. 5.11.

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I got stuck with this problem. Can you help? I fear I didn't identify all the forces required

5. For the structure shown, if h=200 mm, determine
the reactions at A and B.
(Answer: RA=519 N
12.6° RB 586 N 30°
300 mm
T
250
mm
с
250
mm
180 N
oy.
160⁰

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I was getting closer to the answer but for some reason, I get a different result despite I found all the right forces. Could you please tell me what I am doing wrong? As there are no all the steps how you got to the final result. Also, why Rbcos60 has a negative sign? Isn't it making a positive moment so it should have a positive sign instead?

Q3m
Freebody diagram
0.25m 0.25m
Ax
A4
A
G
Take
+5 EM₂₁₂=0
Mg
B
Mathematical Representation.
mament at
up 5 the
น
A
X
RB5n60
Mg-0.25
9
(sin60.0.2 + c0560.0.5.
160 RBC0560
+ (RBSINGO.0.2) + (RBC0660 0.5)-(Mg⋅ 0.25) = 0
RB (Sin60.0.2 + Cos60.0.5). Me .0.25
€0560.0.5) -
RB-

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