I can't figure out where I am going wrong with this problem can you please help me with this? The rod is supported by a ball-and-socket joint A andcables BC and BD. Suppose that F = 850 N.(Figure 1)Figure-3 mF2 m2mA-3 m1 of 1D3 mDetermine the x, y, and z components of reaction at A necessary for equilibrium of the rod using scalarnotation.Express your answers using three significant figures separated by commas.Az. Ay, Az = 425,0,2550Submitνπ ΑΣΦ | | vecPart BX Incorrect; Try Again; 4 attempts remainingPrevious Answers Request AnswerTBC =Determine the tension in the cable BC necessary for equilibrium of the rod.Express your answer to three significant figures and include the appropriate units.μAValueUnits??NReview

The force components along the BC-The force along the BD-

Answered: orted by a ball-and-socket joint A and…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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I can't figure out where I am going wrong with this problem can you please help me with this?

The rod is supported by a ball-and-socket joint A and
cables BC and BD. Suppose that F = 850 N.
(Figure 1)
Figure
-3 m
F
2 m
2m
A
-3 m
1 of 1
D
3 m
Determine the x, y, and z components of reaction at A necessary for equilibrium of the rod using scalar
notation.
Express your answers using three significant figures separated by commas.
Az. Ay, Az = 425,0,2550
Submit
νπ ΑΣΦ | | vec
Part B
X Incorrect; Try Again; 4 attempts remaining
Previous Answers Request Answer
TBC =
Determine the tension in the cable BC necessary for equilibrium of the rod.
Express your answer to three significant figures and include the appropriate units.
μA
Value
Units
?
?
N
Review

Expert Solution

Step 1: Write the force components-

The force components along the BC-

$table row cell F subscript B C end subscript end cell equals cell F subscript B C end subscript open parentheses fraction numerator r subscript B C end subscript over denominator open vertical bar r subscript B C end subscript close vertical bar end fraction close parentheses end cell row blank equals cell F subscript B C end subscript open square brackets fraction numerator negative 6 i minus 2 j plus 3 k over denominator square root of open parentheses negative 6 close parentheses squared plus open parentheses negative 2 close parentheses squared plus 3 squared end root end fraction close square brackets end cell row blank equals cell open parentheses negative 6 over 7 F subscript B C end subscript close parentheses i plus open parentheses negative 2 over 7 F subscript B C end subscript close parentheses j plus open parentheses 3 over 7 F subscript B C end subscript close parentheses k space space space space space space space...... open parentheses 1 close parentheses end cell end table$

The force along the BD-

$table row cell F subscript B D end subscript end cell equals cell F subscript B D end subscript open parentheses fraction numerator r subscript B D end subscript over denominator open vertical bar r subscript B D end subscript close vertical bar end fraction close parentheses end cell row blank equals cell F subscript B D end subscript open square brackets fraction numerator negative 6 i plus 2 j plus 3 k over denominator square root of open parentheses negative 6 close parentheses squared plus open parentheses negative 2 close parentheses squared plus 3 squared end root end fraction close square brackets end cell row blank equals cell open parentheses negative 6 over 7 F subscript B D end subscript close parentheses i plus open parentheses 2 over 7 F subscript B D end subscript close parentheses j plus open parentheses 3 over 7 F subscript B D end subscript close parentheses k space space space space space space space.... open parentheses 2 close parentheses end cell end table$