Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1,720 and a standard deviation of $95. a) determine the interval warranty from various companies that are one standard deviation around the mean. -The interval of warranty costs that are one standard deviation around the mean ranges from $__ to $__. b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean. -the interval of warranty costs that are two standard deviations around the mean ranges from $__ to $__. c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean. -the interval of warranty costs that are three standard deviations around the mean ranges from $__ to $__. Please help with these 3 questions! Thank you! Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1,720 and a standard deviation of $95. Complete parts (a) through (d) below.a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean.The interval of warranty costs that are one standard deviation around the mean ranges from $ __ to $ __.(Type integers or decimals. Use ascending order.)b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean.The interval of warranty costs that are two standard deviations around the mean ranges from $ __ to $ __.(Type integers or decimals. Use ascending order.)c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean.The interval of warranty costs that are three standard deviations around the mean ranges from $ __ to $ __.(Type integers or decimals. Use ascending order.)d) An extended 100,000 mile warranty for this type of vehicle is advertised at $2,100. Based on the previous results, what conclusions can you make?- O A. The $2,100 cost of this warranty must be an error in the advertisement because a data value cannot be more than three standard deviations from the mean.- O B. This warranty is better quality than warranties offered by competing companies due to the fact that it is more than three standard deviations above the mean.- O C. The $2,100 cost of this warranty is much higher than average due to the fact that it is more than three standard deviations above the mean.- O D. The $2,100 cost of this warranty is slightly higher than average due to the fact that it is more than three standard deviations above the mean.

From the provided information, Mean (µ) = $1,720 Standard deviation (σ) = $95 a) The required…

Answered: Assume the cost of an extended 100,000…

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Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1,720 and a standard deviation of $95.

a) determine the interval warranty from various companies that are one standard deviation around the mean.

-The interval of warranty costs that are one standard deviation around the mean ranges from $__ to $__.

b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean.

-the interval of warranty costs that are two standard deviations around the mean ranges from $__ to $__.

c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean.

-the interval of warranty costs that are three standard deviations around the mean ranges from $__ to $__.

Please help with these 3 questions! Thank you!

Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1,720 and a standard deviation of $95. Complete parts (a) through (d) below.

a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean.

The interval of warranty costs that are one standard deviation around the mean ranges from $ __ to $ __.
(Type integers or decimals. Use ascending order.)

b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean.

The interval of warranty costs that are two standard deviations around the mean ranges from $ __ to $ __.
(Type integers or decimals. Use ascending order.)

c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean.

The interval of warranty costs that are three standard deviations around the mean ranges from $ __ to $ __.
(Type integers or decimals. Use ascending order.)

d) An extended 100,000 mile warranty for this type of vehicle is advertised at $2,100. Based on the previous results, what conclusions can you make?

- O A. The $2,100 cost of this warranty must be an error in the advertisement because a data value cannot be more than three standard deviations from the mean.
- O B. This warranty is better quality than warranties offered by competing companies due to the fact that it is more than three standard deviations above the mean.
- O C. The $2,100 cost of this warranty is much higher than average due to the fact that it is more than three standard deviations above the mean.
- O D. The $2,100 cost of this warranty is slightly higher than average due to the fact that it is more than three standard deviations above the mean.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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