2. For the data in the table below, find the sum of the absolute deviations for the predicted values given by the median-median line, y= 3.6x-0.4. 13 2 7 39 4 14 5 15 6 21 7 25 AV
Minimization
In mathematics, traditional optimization problems are typically expressed in terms of minimization. When we talk about minimizing or maximizing a function, we refer to the maximum and minimum possible values of that function. This can be expressed in terms of global or local range. The definition of minimization in the thesaurus is the process of reducing something to a small amount, value, or position. Minimization (noun) is an instance of belittling or disparagement.
Maxima and Minima
The extreme points of a function are the maximum and the minimum points of the function. A maximum is attained when the function takes the maximum value and a minimum is attained when the function takes the minimum value.
Derivatives
A derivative means a change. Geometrically it can be represented as a line with some steepness. Imagine climbing a mountain which is very steep and 500 meters high. Is it easier to climb? Definitely not! Suppose walking on the road for 500 meters. Which one would be easier? Walking on the road would be much easier than climbing a mountain.
Concavity
In calculus, concavity is a descriptor of mathematics that tells about the shape of the graph. It is the parameter that helps to estimate the maximum and minimum value of any of the functions and the concave nature using the graphical method. We use the first derivative test and second derivative test to understand the concave behavior of the function.
![**Question 2:**
For the data in the table below, find the sum of the absolute deviations for the predicted values given by the median-median line, \( y = 3.6x - 0.4 \).
| x | y |
|---|----|
| 1 | 3 |
| 2 | 7 |
| 3 | 9 |
| 4 | 14 |
| 5 | 15 |
| 6 | 21 |
| 7 | 25 |
**Choices:**
- A) 5.7145
- B) 4.8
- C) 4
- D) 0.0005
In this exercise, students are asked to calculate the sum of the absolute deviations between the actual y-values and the predicted y-values from the equation of the median-median line.
**Graph/Diagram Explanation:**
This table displays two columns of data labeled \( x \) and \( y \). The goal is to apply the regression equation \( y = 3.6x - 0.4 \) to predict y-values and determine the deviations from actual y-values listed. After finding the predicted values, calculate the absolute deviations by determining the absolute differences between each pair of actual and predicted values, then sum these differences. This will help in assessing how well the median-median line fits the given data points.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f35f376-ff20-435c-a0e5-f699a7fdde3b%2F2ee014ad-c63b-4bbb-b7be-3fc17b6b124f%2Fowsytwn_processed.jpeg&w=3840&q=75)
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