In what range would you expect to find the middle 95% of hate crimes per year? Between Incorrect and Incorrect. If you were to draw a sample of 10 years worth of hate crimes, in what range would you expect to find the middle 95% of average number of Hate Crimes per year in this sample? Between Incorrect a

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The average number of Hate Crimes in the United States per year (1991 to 2018) is approximately 7900 per year with a standard deviation of approximately 1200 hate crimes per year.

In what range would you expect to find the middle 95% of hate crimes per year?
Between Incorrect and Incorrect.

If you were to draw a sample of 10 years worth of hate crimes, in what range would you expect to find the middle 95% of average number of Hate Crimes per year in this sample?
Between Incorrect a

Expert Solution
Step 1

The random variable X is defined as the number of Hate Crimes in the United States which follows normal distribution with mean 7,900, and standard deviation 1,200.

The range of the middle 95% of Hate Crimes per year in this sample is,

Px1<X<x2=0.95Px1-7,9001,200<X-μσ<x2-7,9001,200=0.95Px1-7,9001,200<z<x2-7,9001,200=0.95

For

1-α=0.95α=0.05α2=0.0251-α2=0.975

The probability 0.975 would be converted to z score can be obtained using the excel formula “=NORM.S.INV(0.975)”. The z score value is 1.96.

The probability 0.025 would be converted to z score can be obtained using the excel formula “=NORM.S.INV(0.025)”. The z score value is -1.96.

The required value is,

Px1-7,9001,200<z<x2-7,9001,200=0.95Px1-7,9001,200<z<x2-7,9001,200=P-1.96<z<1.96

Comparing on both sides.

x1-7,9001,200=-1.96                and        x2-7,9001,200=1.96x1-7,900=-2,352             and           x2-7,900=2,352x1=7,900-2,352   and                         x2=7,900+2,352x1=5,548                 and                         x2=10,252

Thus, the range of the middle 95% of hate crimes per year is between 5,548 and 10,252.

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