Assume that the paired data came from a population that is normally distributed. Using a0.05significance level andd=x−y,findd,sd,the t test statistic, and the critical values to test the claim thatμd=0.x12515759187 y13510101051511 d=(Round to three decimal places as needed.) sd= t= t a/2=

State the hypotheses. That is, there is no difference between two population means. That is, there is difference between two population means. Obtain the value of d. Thus, the value of d is –0.125. Obtain the value of sd. The value of sd is obtained below as follows : Thus, the value of sd is 3.796145. Obtain the value of the test statistic. The value of test statistic is obtained below as follows: The required value of test statistic is, Thus, the value of the test statistic is –0.093. Use EXCEL Procedure for finding the critical value of t. Follow the instruction to obtain the critical value of t: Open EXCEL Go to Formula bar. In formula bar enter the function as“=TINV” Enter the probability as 0.05. Enter the degrees of freedom as 7. Click enter EXCEL output: From the EXCEL output, the critical value of t at the 0.05 level of significance at the 7 degrees of freedom is 2.365. Conclusion: Use the level of significance is 0.05. The test statistic value is –0.093 and the critical value is –2.365. By rejection rule, do not reject the null hypothesis. That is, there is no difference between two population means.

Answered: Assume that the paired data came from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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Assume that the paired data came from a population that is normally distributed. Using a

0.05

significance level and

d=x−y,

find

sd,

the t test statistic, and the critical values to test the claim that

μd=0.

x	12	5	15	7	5	9	18	7
y	13	5	10	10	10	5	15	11

(Round to three decimal places as needed.)

sd=

t a/2=

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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