The following data represent the results from an independent-measures study comparing two treatment conditions. Treatment I II 10 7 N = 16 8 4 G = 120 7 9 ∑X² = 1036 9 3 13 7 7 6 6 10 12 2 M = 9.000 M = 6.000 T = 72 T = 48 SS = 44 SS = 56 Use an independent-measures t test with α = .05 to determine whether there is a significant mean difference between the two treatments. (Use three decimal places; subtract MIIII from MII.) t-critical = ± t = t Distribution Degrees of Freedom = 21 -3.0-2.0-1.00.01.02.03.0t Conclusion: Fail to reject the null hypothesis; there are significant differences between the two treatments. Reject the null hypothesis; there are significant differences between the two treatments. Fail to reject the null hypothesis; there are no significant differences between the two treatments. Reject the null hypothesis; there are no significant differences between the two treatments. Use an ANOVA with α = .05 to determine whether there is a significant mean difference between the two treatments. You should find that F = t². (Round to two decimal places where needed.) Source SS df MS F Fcriticalcritical Between treatments Within treatments Total F Distribution Numerator Degrees of Freedom = 6 Denominator Degrees of Freedom = 16 0.01.02.03.04.05.06.07.08.09.010.011.012.0F Conclusion: Reject the null hypothesis; there are significant differences among the three treatments. Reject the null hypothesis; there are no significant differences among the three treatments. Fail to reject the null hypothesis; there are no significant differences among the three treatments. Fail to reject the null hypothesis; there are significant differences among the three treatments.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

The following data represent the results from an independent-measures study comparing two treatment conditions.

Treatment
I	II
10	7	N = 16
8	4	G = 120
7	9	∑X² = 1036
9	3
13	7
7	6
6	10
12	2
M = 9.000	M = 6.000
T = 72	T = 48
SS = 44	SS = 56

Use an independent-measures t test with α = .05 to determine whether there is a significant mean difference between the two treatments. (Use three decimal places; subtract MIIII from MII.)

t-critical	=	±
t	=

t Distribution

Degrees of Freedom = 21

-3.0-2.0-1.00.01.02.03.0t

Conclusion:

Fail to reject the null hypothesis; there are significant differences between the two treatments.

Reject the null hypothesis; there are significant differences between the two treatments.

Fail to reject the null hypothesis; there are no significant differences between the two treatments.

Reject the null hypothesis; there are no significant differences between the two treatments.

Use an ANOVA with α = .05 to determine whether there is a significant mean difference between the two treatments. You should find that F = t². (Round to two decimal places where needed.)