Assume that the matrix A is row equivalent to B. Find a basis for the row space of the matrix A. 3 -4 0 -2 3 0 -8 0 0 0 1 3 -4 2 4 -5 1 -5 -3 -1 11 5 -2 1 5 -4 3) A = -3 2 -23 17 3 -4 A) {(1, 3, - 4, 0, 1), (2, 4, -5, 5), -2, (1, -5, 0, -3, 2), (-3, - 1, 8, 3, -4)} B) {(1, 3, -4, 0, 1), (0, -2, 3, 5, -4), (0, 0, -8, -23, 17), (0, 0, 0, 0, 0)} C) {(1, 3, -4, 0, 1), (0, -2, 3, 5, -4), (0, 0, -8, -23, 17)} D) {(1,0, 0, 0), (3, -2, 0, 0), (-4, 3, -8, 0)} B.

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Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.