Find the change-of-coordinates matrix from B to the standard basis in R". 2 -2 3 8 -2 7 8. Pa

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**Linear Algebra: Change-of-Coordinates Matrix**

**Problem Statement:**
This exercise involves finding the change-of-coordinates matrix from the given basis \( B \) to the standard basis in \( \mathbb{R}^n \).

**Given Basis:**
\[ B = \left\{ \begin{pmatrix} 2 \\ 8 \\ 7 \end{pmatrix}, \begin{pmatrix} -2 \\ 0 \\ -5 \end{pmatrix}, \begin{pmatrix} 3 \\ -2 \\ 8 \end{pmatrix} \right\} \]

**Question:**
Find the change-of-coordinates matrix from \( B \) to the standard basis in \( \mathbb{R}^n \).

The change-of-coordinates matrix \( P_B \) will be displayed below the problem statement, typically as follows:

\[ P_B = \boxed{ \ \ \ } \]

**Explanation:**
The basis \( B \) is composed of three vectors in \( \mathbb{R}^3 \). The vectors are:
1. \( \begin{pmatrix} 2 \\ 8 \\ 7 \end{pmatrix} \)
2. \( \begin{pmatrix} -2 \\ 0 \\ -5 \end{pmatrix} \)
3. \( \begin{pmatrix} 3 \\ -2 \\ 8 \end{pmatrix} \)

To find the change-of-coordinates matrix \( P_B \), we need to form a matrix whose columns are these three vectors. This matrix, once inverted, will serve as the change-of-coordinates matrix from the given basis \( B \) to the standard basis in \( \mathbb{R}^n \).

**Detailed Steps (for educational clarity):**
1. **Form the Matrix \( B \)** with the vectors as columns.
\[ B = \begin{pmatrix} 2 & -2 & 3 \\ 8 & 0 & -2 \\ 7 & -5 & 8 \end{pmatrix} \]

2. **Compute the Inverse \( B^{-1} \)**. The result of this inversion will be the required change-of-coordinates matrix \( P_B \).

\[ P_B = B^{-1} \]

3. **Output the Matrix \( P_B \)**.

**Note:**
Finding the inverse of a matrix
Transcribed Image Text:**Linear Algebra: Change-of-Coordinates Matrix** **Problem Statement:** This exercise involves finding the change-of-coordinates matrix from the given basis \( B \) to the standard basis in \( \mathbb{R}^n \). **Given Basis:** \[ B = \left\{ \begin{pmatrix} 2 \\ 8 \\ 7 \end{pmatrix}, \begin{pmatrix} -2 \\ 0 \\ -5 \end{pmatrix}, \begin{pmatrix} 3 \\ -2 \\ 8 \end{pmatrix} \right\} \] **Question:** Find the change-of-coordinates matrix from \( B \) to the standard basis in \( \mathbb{R}^n \). The change-of-coordinates matrix \( P_B \) will be displayed below the problem statement, typically as follows: \[ P_B = \boxed{ \ \ \ } \] **Explanation:** The basis \( B \) is composed of three vectors in \( \mathbb{R}^3 \). The vectors are: 1. \( \begin{pmatrix} 2 \\ 8 \\ 7 \end{pmatrix} \) 2. \( \begin{pmatrix} -2 \\ 0 \\ -5 \end{pmatrix} \) 3. \( \begin{pmatrix} 3 \\ -2 \\ 8 \end{pmatrix} \) To find the change-of-coordinates matrix \( P_B \), we need to form a matrix whose columns are these three vectors. This matrix, once inverted, will serve as the change-of-coordinates matrix from the given basis \( B \) to the standard basis in \( \mathbb{R}^n \). **Detailed Steps (for educational clarity):** 1. **Form the Matrix \( B \)** with the vectors as columns. \[ B = \begin{pmatrix} 2 & -2 & 3 \\ 8 & 0 & -2 \\ 7 & -5 & 8 \end{pmatrix} \] 2. **Compute the Inverse \( B^{-1} \)**. The result of this inversion will be the required change-of-coordinates matrix \( P_B \). \[ P_B = B^{-1} \] 3. **Output the Matrix \( P_B \)**. **Note:** Finding the inverse of a matrix
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