If A and B are similar, then there exists a matrix P such that Bk = p-1akp. Use this fact to find B5, where B = p-1AP, for the matrices 1 0 3 B = -1 -1 1 1 -1 p-1 = A = 0 2 P = -2 2 -1 125 -62 B5 = 186 -92

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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If A and B are similar, then there exists a matrix P such that Bk = p-1akp. Use this fact to find B5, where B =
p-1AP, for the matrices
1 0
3
B =
-1
-1 1
1 -1
p-1 =
A =
0 2
P =
-2
2 -1
125
-62
B5 =
186
-92
Transcribed Image Text:If A and B are similar, then there exists a matrix P such that Bk = p-1akp. Use this fact to find B5, where B = p-1AP, for the matrices 1 0 3 B = -1 -1 1 1 -1 p-1 = A = 0 2 P = -2 2 -1 125 -62 B5 = 186 -92
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