Assume that the launching and landing position of the steel ball are at the same height. (y; =Y;) The mass of the steel ball is 45 g, the initial speed of the ball is 3.85 m/s and the angle at which the ball is released is given as 55°. a) Which formula do we use to calculate the time of flight? OAt= (v;*sin(8))/g(2*v;*sin(8))/g(g*v;*sin(0))/2 (v;*sin(0))/2*g OAt= OAt= OAt=

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Assume that the launching and landing
position of the steel ball are at the same
height. (y; = Yf)
The mass of the steel ball is 45 g, the initial
speed of the ball is 3.85 m/s and the angle at
which the ball is released is given as 55º.
a) Which formula do we use to calculate the
time of flight?
Oat=
OAt=
OAt=
OAt=
(v,*sin(0))/g(2*v;*sin(0))/g(g*v;*sin(e))/2 (v;*sin(e))/2*g
Transcribed Image Text:Assume that the launching and landing position of the steel ball are at the same height. (y; = Yf) The mass of the steel ball is 45 g, the initial speed of the ball is 3.85 m/s and the angle at which the ball is released is given as 55º. a) Which formula do we use to calculate the time of flight? Oat= OAt= OAt= OAt= (v,*sin(0))/g(2*v;*sin(0))/g(g*v;*sin(e))/2 (v;*sin(e))/2*g
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