An archer shoots an 18.0-gram arrow at a 43.0-gram target on a wall 32.0 m high. If the arrow is shot at a velocity of vo = 60.0 m/s, what is the speed of the arrow when it reaches the target? %3D Substitute values in the above equation v=/(60. 0)² – 2 (9. 8) (32. 0) =54. 52 "/ If the arrow is embedded in the target and they both fly off the wall together in an inelastic collision, at what speed will they leave the wall?
An archer shoots an 18.0-gram arrow at a 43.0-gram target on a wall 32.0 m high. If the arrow is shot at a velocity of vo = 60.0 m/s, what is the speed of the arrow when it reaches the target? %3D Substitute values in the above equation v=/(60. 0)² – 2 (9. 8) (32. 0) =54. 52 "/ If the arrow is embedded in the target and they both fly off the wall together in an inelastic collision, at what speed will they leave the wall?
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Could you help me with the highlightled part. Not sure which velocity to use, V intial when arrow was shot or V when arrow was embedded in target.
![**Problem Statement:**
An archer shoots an 18.0-gram arrow at a 43.0-gram target on a wall 32.0 m high. If the arrow is shot at a velocity of \( v_0 = 60.0 \, \text{m/s} \), what is the speed of the arrow when it reaches the target?
**Solution:**
Substitute values in the above equation:
\[
v = \sqrt{(60.0)^2 - 2 \cdot (9.8) \cdot (32.0)}
\]
\[
= 54.52 \, \text{m/s}
\]
**Further Question:**
If the arrow is embedded in the target and they both fly off the wall together in an inelastic collision, at what speed will they leave the wall?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54fc09bc-9289-41c3-be9b-97e080f2b9a5%2F27888af0-f1b6-47f4-9e97-7b9b831c60e8%2F7nwcikq_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An archer shoots an 18.0-gram arrow at a 43.0-gram target on a wall 32.0 m high. If the arrow is shot at a velocity of \( v_0 = 60.0 \, \text{m/s} \), what is the speed of the arrow when it reaches the target?
**Solution:**
Substitute values in the above equation:
\[
v = \sqrt{(60.0)^2 - 2 \cdot (9.8) \cdot (32.0)}
\]
\[
= 54.52 \, \text{m/s}
\]
**Further Question:**
If the arrow is embedded in the target and they both fly off the wall together in an inelastic collision, at what speed will they leave the wall?
Expert Solution
Step 1
In an elastic collision, momentum is conserved before and after collision,
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