A ball is struck from a height (1.80 m) with an initial velocity of 12.0 m/s at an angle of 42.0° above the horizontal. The ball passes through the center of a hoop before returning to the ground which is 1.80 m below the starting point. If the ball is moving horizontally when it goes through the hoop, (hint: make sure you know the condition of equations you want to use.) use g=9.81m/s? 1. how long does it take to reach the hoop? 2. And how high above the ground is the center of the hoop? 3. How far is the ball measured horizontally from the person to where it landed? 40.0° 2.00
A ball is struck from a height (1.80 m) with an initial velocity of 12.0 m/s at an angle of 42.0° above the horizontal. The ball passes through the center of a hoop before returning to the ground which is 1.80 m below the starting point. If the ball is moving horizontally when it goes through the hoop, (hint: make sure you know the condition of equations you want to use.) use g=9.81m/s? 1. how long does it take to reach the hoop? 2. And how high above the ground is the center of the hoop? 3. How far is the ball measured horizontally from the person to where it landed? 40.0° 2.00
Related questions
Question
![A ball is struck from a height (1.80 m) with an initial velocity of 12.0 m/s at an
angle of 42.0° above the horizontal. The ball passes through the center of a
hoop before returning to the ground which is 1.80 m below the starting
point. If the ball is moving horizontally when it goes through the hoop, (hint:
make sure you know the condition of equations you want to use.)
use g=9.81m/s²
1. how long does it take to reach the hoop?
2. And how high above the ground is the center of the hoop?
3. How far is the ball measured horizontally from the person to where it
landed?
40.0°
2.00
m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2652b5e9-a8be-4cd2-83a2-3c03f5281909%2Faf273b70-2369-402a-a18e-d57e1e43c13a%2Ffe61dw_processed.png&w=3840&q=75)
Transcribed Image Text:A ball is struck from a height (1.80 m) with an initial velocity of 12.0 m/s at an
angle of 42.0° above the horizontal. The ball passes through the center of a
hoop before returning to the ground which is 1.80 m below the starting
point. If the ball is moving horizontally when it goes through the hoop, (hint:
make sure you know the condition of equations you want to use.)
use g=9.81m/s²
1. how long does it take to reach the hoop?
2. And how high above the ground is the center of the hoop?
3. How far is the ball measured horizontally from the person to where it
landed?
40.0°
2.00
m
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)