Assume that the AC generator has a sine wave output across its terminals A and B. The peak value of the output voltage is 100V. AC GENERATOR Figure 13-1. a. On the graph of Figure 13-2, draw the sine wave output voltage of the generator. Plot your voltage points at 15° intervals (starting from 0° to 360°). b. Draw a smooth curve through all of your plotted points and label this voltage curve "e". Note: The abbreviations for instantaneous voltage are "e" and "vas opposed to the conventional "E" and "V".

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Assume that the AC generator has a sine wave output across its
terminals A and B. The peak value of the output voltage is 100V.
AC
GENERATOR
Figure 13-1.
a. On the graph of Figure 13-2, draw the sine wave output voltage of the
generator. Plot your voltage points at 15° intervals (starting from 0° to
360°).
b. Draw a smooth curve through all of your plotted points and label this
voltage curve "e".
Note: The abbreviations for instantaneous voltage are "e" and
"vas opposed to the conventional "E" and V".
O 2. From your graph, read off the instantaneous voltage value (v) for each of
the following angles. Record your readings and state whether the polarity
is positive or negative.
20° e =
40° e =
80° e =
220° e =
310° e =
350° e =
Transcribed Image Text:Assume that the AC generator has a sine wave output across its terminals A and B. The peak value of the output voltage is 100V. AC GENERATOR Figure 13-1. a. On the graph of Figure 13-2, draw the sine wave output voltage of the generator. Plot your voltage points at 15° intervals (starting from 0° to 360°). b. Draw a smooth curve through all of your plotted points and label this voltage curve "e". Note: The abbreviations for instantaneous voltage are "e" and "vas opposed to the conventional "E" and V". O 2. From your graph, read off the instantaneous voltage value (v) for each of the following angles. Record your readings and state whether the polarity is positive or negative. 20° e = 40° e = 80° e = 220° e = 310° e = 350° e =
+ 100
+ 80
+ 60
+ 40
+ 20
-20
-40
-60
-80
-100
0° 30°
60 90°
120° 150 180° 210°
240°
270
300 330
360
ANGULAR ROTATION IN DEGREES
Figure 13-2.
INSTANTANEOUS VOLTAGE (e) 0R CURRENT (i)
品
INSTANTANEOUS POWER IN THOUSANDS OF WATTS
Transcribed Image Text:+ 100 + 80 + 60 + 40 + 20 -20 -40 -60 -80 -100 0° 30° 60 90° 120° 150 180° 210° 240° 270 300 330 360 ANGULAR ROTATION IN DEGREES Figure 13-2. INSTANTANEOUS VOLTAGE (e) 0R CURRENT (i) 品 INSTANTANEOUS POWER IN THOUSANDS OF WATTS
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