Assume that if the shear stress in steel exceeds about 4.00 x 108 N/m², the steel ruptures. Step 1 (a) Determine the shearing force necessary to shear a steel bolt 1.05 cm in diameter. (b) Determine the shearing force necessary to punch a 1.05-cm-diameter hole in a steel plate 0.840 cm thick. (a) We know that force F is equal to the surface area A times stress σ so we have FOA 4.00 ✓ × 108 108 N/m²)( X Your response differs from the correct answer by more than 10%. Double check your calculations. x 10-2 10-2 m)² 4200000 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. x F F d 104 N.
Assume that if the shear stress in steel exceeds about 4.00 x 108 N/m², the steel ruptures. Step 1 (a) Determine the shearing force necessary to shear a steel bolt 1.05 cm in diameter. (b) Determine the shearing force necessary to punch a 1.05-cm-diameter hole in a steel plate 0.840 cm thick. (a) We know that force F is equal to the surface area A times stress σ so we have FOA 4.00 ✓ × 108 108 N/m²)( X Your response differs from the correct answer by more than 10%. Double check your calculations. x 10-2 10-2 m)² 4200000 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. x F F d 104 N.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter14: Static Equilibrium, Elasticity, And Fracture
Section: Chapter Questions
Problem 49PQ
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
Transcribed Image Text:Assume that if the shear stress in steel exceeds about 4.00 x 108 N/m², the steel ruptures.
Step 1
(a) Determine the shearing force necessary to shear a steel bolt 1.05 cm in diameter.
(b) Determine the shearing force necessary to punch a 1.05-cm-diameter hole in a steel plate 0.840 cm thick.
(a) We know that force F is equal to the surface area A times stress σ so we have
FOA
4.00
✓ × 108
108 N/m²)(
X
Your response differs from the correct answer by more than 10%. Double check your calculations. x 10-2
10-2 m)²
4200000
X
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. x
F
F
d
104 N.
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