Assume that adults have IQ scores that are normally distributed with a mean of 103.4 and a standard deviation 21.5. first quartile Q,, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is (Type an integer or decimal rounded to one decimal place as needed.)

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## Transcription for Educational Website

### Problem Statement:
Assume that adults have IQ scores that are normally distributed with a mean of 103.4 and a standard deviation of 21.5. Find the first quartile \( Q_1 \), which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.)

### Solution:
The first quartile is \( \_\_\_ \).

(Type an integer or decimal rounded to one decimal place as needed.)

---

### Explanation of Graphs/Diagrams:
In addressing this problem, a normal distribution curve can be drawn to visualize the IQ scores. The curve will peak at the mean (103.4) and symmetrically decline towards each side. To determine the first quartile \( Q_1 \), calculate the IQ score at which 25% of the distribution lies below it. This requires using the properties of the normal distribution to find the respective z-score and convert it to the IQ scale with the given mean and standard deviation.
Transcribed Image Text:## Transcription for Educational Website ### Problem Statement: Assume that adults have IQ scores that are normally distributed with a mean of 103.4 and a standard deviation of 21.5. Find the first quartile \( Q_1 \), which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) ### Solution: The first quartile is \( \_\_\_ \). (Type an integer or decimal rounded to one decimal place as needed.) --- ### Explanation of Graphs/Diagrams: In addressing this problem, a normal distribution curve can be drawn to visualize the IQ scores. The curve will peak at the mean (103.4) and symmetrically decline towards each side. To determine the first quartile \( Q_1 \), calculate the IQ score at which 25% of the distribution lies below it. This requires using the properties of the normal distribution to find the respective z-score and convert it to the IQ scale with the given mean and standard deviation.
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