Assume an instruction: 0x00c6ba23 is located in memory at address: Answer the following questions when the instruction is executed based on the datapath and control shown in Figure 4.17.a). What are the values of the ALU Control to the ALU unit?b) What is the PC address after this instruction is executed?c)What is the values (either 0 or 1) of the control signals to the three multiplexers?d) What are the input values for the ALU? 4.4 A Simple Implementation Scheme257Add4Add SumShiftleft 1BranchMemReadMemtoRegInstruction [6-0]Control ALU0PMemWriteALUSrcRegWriteInstruction [19-15]ReadaddressReadregister 1 Readdata 1PCInstruction [24-20]ReadZeroInstructionregister 2[31-0]ALU ALUReadAddress dataInstruction [11-7]ReadWriteregister data 2resultInstructionmemoryWritedata RegistersDataWritedata memoryInstruction [31-0]3264ImmGenALUcontrolInstruction [30,14-12]FIGURE 4.17 The simple datapath with the control unit. The input to the control unit is the 7-bit opcode field from the instruction.The outputs of the control unit consist of two 1-bit signals that are used to control multiplexors (ALUSrc and MemtoReg), three signals forcontrolling reads and writes in the register file and data memory (RegWrite, MemRead, and MemWrite), a 1-bit signal used in determiningwhether to possibly branch (Branch), and a 2-bit control signal for the ALU (ALUOP). An AND gate is used to combine the branch controlsignal and the Zero output from the ALU; the AND gate output controls the selection of the next PC. Notice that PCSrc is now a derived signal,rather than one coming directly from the control unit. Thus, we drop the signal name in subsequent figures.

Name: Assume an instruction: 0x00c6ba23 is located in memory at address: A
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: Assume an instruction: 0x00c6ba23 is located in memory at address: Answer the following questions when the instruction is executed based on the datapath and control shown in Figure 4.17.a). What are the values of the ALU Control to the ALU unit?b)