Assume a Normal distribution. What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for the difference between two dependent population means t-test for a population mean z-test for a population proportion z-test for the difference between two population proportions t-test for the difference between two independent population means The null and alternative hypotheses would be: H0:H0: Select an answer μ1 μd p1 Select an answer < > = ≠ Select an answer 0 p2 μ2 (please enter a decimal) H1:H1: Select an answer p1 μd μ1 Select an answer < > ≠ = Select an answer 0 μ2 p2 (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the population mean test score taking the exam alone is less than the population mean test score taking the exam in a classroom setting. The results are statistically insignificant at αα = 0.05, so there is statistically significant evidence to conclude that the population mean test score taking the exam alone is equal to the population mean test score taking the exam in a classroom setting. The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the eight students scored lower on average taking the exam alone compared to the classroom setting. The results are statistically insignificant at αα = 0.05, so there is insufficient evidence to conclude that the population mean test score taking the exam alone is less than the population mean test score taking the exam in a classroom setting.
Do students perform worse when they take an exam alone than when they take an exam in a classroom setting? Eight students were given two tests of equal difficulty. They took one test in a solitary room and they took the other in a room filled with other students. The results are shown below.
Exam Scores
Alone | 92 | 86 | 78 | 83 | 76 | 75 | 71 | 74 |
---|---|---|---|---|---|---|---|---|
Classroom | 93 | 92 | 90 | 89 | 76 | 84 | 72 | 78 |
Assume a
For this study, we should use Select an answer t-test for the difference between two dependent population means t-test for a population
- The null and alternative hypotheses would be:
H0:H0: Select an answer μ1 μd p1 Select an answer < > = ≠ Select an answer 0 p2 μ2 (please enter a decimal)
H1:H1: Select an answer p1 μd μ1 Select an answer < > ≠ = Select an answer 0 μ2 p2 (Please enter a decimal)
- The test statistic ? t z = (please show your answer to 3 decimal places.)
- The p-value = (Please show your answer to 4 decimal places.)
- The p-value is ? > ≤ αα
- Based on this, we should Select an answer reject fail to reject accept the null hypothesis.
- Thus, the final conclusion is that ...
- The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the population mean test score taking the exam alone is less than the population mean test score taking the exam in a classroom setting.
- The results are statistically insignificant at αα = 0.05, so there is statistically significant evidence to conclude that the population mean test score taking the exam alone is equal to the population mean test score taking the exam in a classroom setting.
- The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the eight students scored lower on average taking the exam alone compared to the classroom setting.
- The results are statistically insignificant at αα = 0.05, so there is insufficient evidence to conclude that the population mean test score taking the exam alone is less than the population mean test score taking the exam in a classroom setting.
Step by step
Solved in 2 steps with 1 images