.6-1Assigned MedlaUse technology to find the P-value for the hypothesis test described below.The claim is that for 12 AM body temperatures, the mean isp>98.6°F The sample size is n=4 and the test statistic is t= 2.446.P-value=(Rbund to three decimal places as needed.)(1,1)MoreEnter your answer in the answer box and then click Check Answer.Clear AllFinal CheckAll parts showingConCopyright 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy Permissionse to searchDEEL

Answered: Image /qna-images/answer/d9cbc5c0-6175-4852-a385-9c2a7af5c4a4.jpg

Assigned Meula Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is u>98.6°F. The sample size is n=4 and the test statistic is t=2.446. P-value = (Rbund to three decimal places as needed.)

Assigned Meula Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is u>98.6°F. The sample size is n=4 and the test statistic is t=2.446. P-value = (Rbund to three decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Answer it correctly please. Explain . I will rate accordingly with multiple votes.
The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use a = 0.01 and assume normality. n- 40, Σd- 207, Σα? = 6199 (a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. O Reject the null hypothesis, there is significant evidence that the coating is beneficial. Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.
A population has parameters u = 62.9 and o = 101. 57.3. You intend to draw a random sample of size n = What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.) Question Help: D Video D Post to forum Submit Question
thill An experiment compares two different processes for producing steel plate. The measurements represent the thickness of the plate. The samples gave m = 8, X = 6.701, S1 = 0.108 n = 6, Y = 6.841, S2 = 0.155 %3D %3D Assume that the two populations are normal with equal variances, test Ho: H1 - H2 = 0 against H1 : µ1 - µ2#0 at a 0.05 significance level. 5.
The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use ? = 0.01 and assume normality. n = 36, Σd = 227, Σd2 = 6244(a) Find t. (Give your answer correct to two decimal places.)(ii) Find the p-value. (Give your answer correct to four decimal places.)(b) State the appropriate conclusion. Reject the null hypothesis, there is significant evidence that the coating is beneficial.Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial.Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
Use the following R output to answer the question. Use the following R output to answer the question. >chisq.test(data) Pearsons Chi-square test data:data X-squared=4.7194, df=2, p-value=0.09445 If the significance level is 5%, what conclusion can you make? Group of answer choices A. fail to reject the alternative hypothesis B. cannot determine C. fail to reject the null hypothesis D. reject the null hypothesis and accept the alternative hypothesis
Use the 5 step method and discuss type 1 and type 2 error. 2. A local bottler, Fossil Cove, wants to ensure that an average of 16 ounces of beer is used to fill each bottle. Ben takes a random sample of 48 bottles and finds the average weight to be 15.8 ounces Historically, the standard deviation has been 0.8 ounces. Alpha is .05.
Is the mean length of adult invasive Lionfish in the Atlantic coast of South Carolina greater than 355.6mm? (don't answer this, this is just so you know what the data is for) Answer the following questions and use the provided excel images, data on the far left is lionfish data Question 2. Describe your null and alternative hypotheses using symbols. Question 3. Select the significance level (a). Question 4. Select an appropriate test, calculate the test statistic and p-value using Excel. Question 5. Determine whether you should reject or not reject the null hypothesis based on the p-value. State the reason to support your answer. Question 6. Describe your conclusion in words in the context of your research question. paste data below Use this sheet to perform a 1-sample t-test. 457.2 431.9 COUNT MEAN 20.00 437.45 438.2 STANDARD DEVIATION 16.48 436.4 STANDARD ERROR 3.69 416.8 454.6 Confidence Interval 95% 456.6 Level of Significance 0.05 453.1 404.9 447.9 437.9 HYPOTHESIS TEST t-VALUE…
A new medication is being developed to treat severe nausea and vomiting among chemotherapy patients. The information below was generated from a small sample size (n = 11) and shows the number of times a chemotherapy patient vomited both before and after treatment due to the side effects of chemotherapy. Set up and interpret the results of a sign test at the alpha equals .05 level to determine if there is a difference in symptoms before and after treatment. Chemotherapy Patient Before Treatment After Treatment Difference Sign 1 9 3 2 12 5 3 14 7 4 9 4 5 8 2 6 11 3 7 15 7 8 12 8 9 7 8 10 9 5 11 8 7 A) We fail to reject H0, which states the median difference in the number of vomiting episodes in a day before and after treatment are equal because 1 is less or equal to critical value 1 for a sign test…
Claim: The mean systolic blood pressure of all healthy adults is less than than 120 mm Hg. Sample data: For 276 healthy adults, the mean systolic blood pressure level is 119.61 mm Hg and the standard deviation is 14.88 mm Hg. The null and alternative hypotheses are Ho: μ = 120 and H₁: μ< 120. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.) C
Please sir or ma’am, please help me with hypothesis, critical region, and t statistic.