QUESTION 12In the video game Animal Crossing: New Horizons, you can catch and sell both fish and sea creatures. Alisonlearns that sea creatures sell for a mean of u = 3,345 bells with a standard deviation of o = 3,684 bells ("bells"is the currency in the game). Alison suspects that fish will sell for more money than sea creatures will, so shedecides to conduct a hypothesis test at the a = 0.01 level with%3D%3DHọ: µ= 3,345 bellsH1: p > 3,345 bellsShe finds a sample of 64 fish and computes their mean price to be 3,527 bells.a. Determine the standard error to the nearest thousandth.Ox =Work:b. Determine the z-score to the nearest hundredth.Z =Work:c. Identify the image below that best represents the standard normal curve you drew for this problem.AВC c. Identify the image below that best represents the standard normal curve you drew for this problem.ACd. State the p-value.p-value =Work:e. Fill-in the blanks: We willthe null hypothesis because the resultsstatistically significant at the a =level.f. Can you conclude that fish will sell for more money than bugs?

Given, Population mean, μ=3345 Standard deviation, σ=3684 Sample mean, X=3527 Sample size, n = 64…

Answered: In the video game Animal Crossing: New…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are applying for a job at two companies. Company A offers starting salaries with u = $33,000 and o = $1,000. Company B offers starting salaries with u = $33,000 and o = $3,000. From which company are you more likely to get an offer of $35,000 or more? Choose the correct answer below. O A. Company A, because data values that lie more than two standard deviations from the mean are considered unusual. O B. No difference, because data values that lie more than three standard deviations from the mean are considered very unusual. O C. Company B, because data values that lie within one standard deviation from the mean are not considered unusual.
Brooke is interested in whether art classes improve students’ attitudes about school. She collects a sample of students who are enrolled in art class and finds that they report a mean of M = 19 on a school-attitudes scale. She knows that the school-attitudes scale has a mean of μ = 15 and a standard deviation of σ = 3. What type of test would you use to test the hypothesis that art classes improve school attitudes? Would you use a one-tailed or two-tailed test? What would be an appropriate measure of effect size to report?
A recent report claims that Americans spend an average of $11 per day on lunch. You believe that people who live in Philadelphia, PA spend significantly less on lunch per day than that. In order to test this, you randomly sampled n=100 Philadelphia residents and asked them how much they spend on lunch everyday. The sample average of these respondents was $10.92 with a sample standard deviation of $1.07. If you want to test the null hypothesis that H0: mean=11 vs Ha: mean <11.what is the value of the test statistic?
Part 1 of 4 Victoria, an accomplished marathon runner, claims that the standard deviation for her time to run a 26.2 mile marathon is less than 17.5 minutes. To test her claim, Victoria looks up 11 of her race times (in minutes): 227.2, 233.3, 259.7, 265.8, 252.1, 228.8, 222.6, 202.9, 214.5, 237.2, 267.7 Perform a hypothesis test using a 9% level of significance to test Victoria's claim. Step 1: State the null and alternative hypotheses. 17.5 Ha:0
The college physical education department offered an advanced first aid course last summer. The scores on the comprehensive final exam were normally distributed, and the z-scores for some of the students are shown below. Robert 1.05 Juan 1.51 Haley −1.95 Joel 0.00 Jan −0.67 Linda 1.57 (a) If the mean score was ? = 151 with standard deviation ? = 16, what was the final exam score for each student?
A new Economic / Social Conservatism Scale has scores between 0 and 30 (0 being extreme liberal, 30 being extreme conservative). The mean score is 21 and standard deviation of scores is 5. You want to convert the original scale (call it X) to a new scale (call it Y) that has scores between 0 and 100. What is the correlation of X and Y?
3. ACT scores are roughly Normal with mean 20.8 and standard deviation 4.8, and SAT scores are roughly Normal with mean 1026 and standard deviation 209. Some students take both. For those students, the correlation between the two scores is 0.72. a. What's the equation of the straight line that you'd use to predict ACT scores based on SAT scores? b. I got a 1300 on the SAT, and I'm planning to take the ACT. Predict what I might get, c. What's the equation of the straight line that you'd use to predict SAT scores based on ACT scores? d. My friend got a 27 on the ACT, and she's planning to take the SAT. Predict what she might get. e. How come you're predicting both that I'll do worse than her on the ACT and that she will do worse than me on the SAT? 4. Draw a simple random nlc of size 15 from the labels 40os01, 402.
Last year, the average amount that teams for the Statistics Games raised was $375. Have teams been more successful at fundraising this year? To find out, you take a random sample of 36 teams. Your sample of 36 teams yields a mean of $396 and a standard deviation of $70. Might you have made a Type 1 or Type 2 error? A Type 1. This means that we said that the mean amount raised had increased, when it was actually still $375. B You might have made a calculation error. C Neither- we're sure the average has increased. D Type 2. This would mean that we said there was not enough evidence to say the mean had increased from $375, when it actually is higher than $375. E Either kind is possible!
A conservationist wants to know if the average water level in Horseshoe Lake is more than the average water level in Swan Lake. A sample of 23 observations from Horseshoe Lake has a mean of 43 meters and a standard deviation of 3.2 meters. A sample of 23 observations from Swan Lake has a mean of 38 meters and a standard deviation of 2.4 meters. Test his hypothesis at a = 0.01. O reject HO; It appears that the average water level in Horseshoe Lake is more than the average water level in Swan Lake. O fail to reject HO; It appears that the average water level in Horseshoe Lake is not more than the average water level in Swan Lake. O not sufficient information to decide
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