Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents.16 н* (аq)2 Cr20,2 (aq) + C2H5OH(/)---> 4 Cr3*(aq)+ 2 CO2(8) + 11 H20(1)+ONs on reactant (LEFT)sideONs on product (RIGHT)sideH =H =Cr =Cr =O =O =C =C =The OA is (choose correct letter) =A. Н|в. Сr2072|с. С 2 H5 ОНD. Cr 3+The RA is (choose correct letter) =А. СО 2|в. Сr2072c. H20D. C 2 H5 ОН

Answered: Image /qna-images/answer/496a9dc7-f46d-4152-8bc9-7f5eb7c63735.jpg

Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents. 16 H*(aq) + 2 Cr2072"(aq) + C2H50H() ---> 4 Cr3*(aq) + 2 Co28) + 11 H20() ONs on reactant (LEFT) side ONs on product (RIGHT) side H = H = Cr = Cr = O = IC = C = The OA is (choose correct letter) = A. H* B. Cr 2072- c. C2H5 OH D. Cr 3+ The RA is (choose correct letter) = A. CO 2 B. Cr2072- c. H20 C2H5 OH

Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents. 16 H(aq) + 2 Cr2072"(aq) + C2H50H() ---> 4 Cr3(aq) + 2 Co28) + 11 H20() ONs on reactant (LEFT) side ONs on product (RIGHT) side H = H = Cr = Cr = O = IC = C = The OA is (choose correct letter) = A. H* B. Cr 2072- c. C2H5 OH D. Cr 3+ The RA is (choose correct letter) = A. CO 2 B. Cr2072- c. H20 C2H5 OH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents.
16 н* (аq)
2 Cr20,2 (aq) + C2H5OH(/)
---> 4 Cr3*(aq)
+ 2 CO2(8) + 11 H20(1)
+
ONs on reactant (LEFT)
side
ONs on product (RIGHT)
side
H =
H =
Cr =
Cr =
O =
O =
C =
C =
The OA is (choose correct letter) =
A. Н
|в. Сr2072
|с. С 2 H5 ОН
D. Cr 3+
The RA is (choose correct letter) =
А. СО 2
|в. Сr2072
c. H20
D. C 2 H5 ОН

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