Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents. 16 H*(aq) + 2 Cr2072"(aq) + C2H50H() ---> 4 Cr3*(aq) + 2 Co28) + 11 H20() ONs on reactant (LEFT) side ONs on product (RIGHT) side H = H = Cr = Cr = O = IC = C = The OA is (choose correct letter) = A. H* B. Cr 2072- c. C2H5 OH D. Cr 3+ The RA is (choose correct letter) = A. CO 2 B. Cr2072- c. H20 C2H5 OH
Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents. 16 H*(aq) + 2 Cr2072"(aq) + C2H50H() ---> 4 Cr3*(aq) + 2 Co28) + 11 H20() ONs on reactant (LEFT) side ONs on product (RIGHT) side H = H = Cr = Cr = O = IC = C = The OA is (choose correct letter) = A. H* B. Cr 2072- c. C2H5 OH D. Cr 3+ The RA is (choose correct letter) = A. CO 2 B. Cr2072- c. H20 C2H5 OH
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents.
16 н* (аq)
2 Cr20,2 (aq) + C2H5OH(/)
---> 4 Cr3*(aq)
+ 2 CO2(8) + 11 H20(1)
+
ONs on reactant (LEFT)
side
ONs on product (RIGHT)
side
H =
H =
Cr =
Cr =
O =
O =
C =
C =
The OA is (choose correct letter) =
A. Н
|в. Сr2072
|с. С 2 H5 ОН
D. Cr 3+
The RA is (choose correct letter) =
А. СО 2
|в. Сr2072
c. H20
D. C 2 H5 ОН](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0c299dc-562f-4f21-8742-5dfc20999103%2F496a9dc7-f46d-4152-8bc9-7f5eb7c63735%2Flbi33xp_processed.png&w=3840&q=75)
Transcribed Image Text:Assign oxidation numbers (ONs) to (i.e., to ONE ATOM only) of each element on both sides of the following equation then identify the oxidizing (OA) and reducing (RA) agents.
16 н* (аq)
2 Cr20,2 (aq) + C2H5OH(/)
---> 4 Cr3*(aq)
+ 2 CO2(8) + 11 H20(1)
+
ONs on reactant (LEFT)
side
ONs on product (RIGHT)
side
H =
H =
Cr =
Cr =
O =
O =
C =
C =
The OA is (choose correct letter) =
A. Н
|в. Сr2072
|с. С 2 H5 ОН
D. Cr 3+
The RA is (choose correct letter) =
А. СО 2
|в. Сr2072
c. H20
D. C 2 H5 ОН
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