When the following equation is balanced properly under basic conditions, what are the coefficients of the species shown? NH3 + HPBO,- Pb + N,H4 Water appears in the balanced equation as a |(reactant, product, neither) with a coefficient of - (Enter 0 for neither.) Which element is oxidized?
When the following equation is balanced properly under basic conditions, what are the coefficients of the species shown? NH3 + HPBO,- Pb + N,H4 Water appears in the balanced equation as a |(reactant, product, neither) with a coefficient of - (Enter 0 for neither.) Which element is oxidized?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:When the following equation is balanced properly under basic conditions, what are the coefficients of the species shown?
NH3 +
HPBO,-
Pb +
N2H4
Water appears in the balanced equation as a
|(reactant, product, neither) with a coefficient of
(Enter 0 for neither.)
Which element is oxidized?
Expert Solution

Step 1
The reaction given is,
=> NH3 + HPbO2- ----------> Pb + N2H4
In the above reaction, N in NH3 is in 3- oxidation state initially (because each H is in 1+ oxidation state) and finally in N2H4 its in 2- oxidation state (because each H is in 1+ oxidation state).
And Pb in HPbO2- is in 2+ oxidation state initially (because O is in 2- oxidation state and H in 1+ and there is 1- in the ion) and finally in 0 oxidation state as Pb.
Since the oxidation state of Pb is decreasing. Hence the Pb is reduced in the reaction.
And since the oxidation state of N is increasing. Hence N is being oxidised in the reaction.
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