Assemble the total stiffness matrix S, the force vectors P, PFEF and the displacement vector D for the whole structure needed to analyze the beam shown below. Use the shown numbering system and EI=constant. 25 kN/m 1 6 m 2 6 m (3)
Assemble the total stiffness matrix S, the force vectors P, PFEF and the displacement vector D for the whole structure needed to analyze the beam shown below. Use the shown numbering system and EI=constant. 25 kN/m 1 6 m 2 6 m (3)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![Assemble the total stiffness matrix S, the force vectors P, PFEF and the displacement vector D
for the whole structure needed to analyze the beam shown below.
Use the shown numbering system and El=constant.
1
k₁
25 kN/m
=
1
200
600
-200 600
600
k22 -600 1200
-200
-600 200 -600
600 1200 -600 2400
Answer the following questions(16-22):
6 m
17. The Value of EI= .... in (kN.m²) is:
a) 200
b) 600
(2)
2
6 m
{P} =[S]{D} + PFEF
d) 3600
c) 2400
18. For member 1, the value of K₂2 =.... in (kN.m²) is:
a) -200
b) -600
c) 2400
19. For member 2, the value of k23 = .... in (kN.m²) is:
a) -200
b) -600
c) 2400
20. For the whole structure, the value of S11
in (kN.m²) is:
b) 3600
c) 2400
a) 200
21. The rotational displacements (0₂) of node (joint) 2 = .... in (radians) is:
c) -0.03245
a) 0.0
b) 0.015625
22. The value of the moment at node 3 (M32) on the bending moment diagram =
a) 0.0
b) +18.75
c) -93.75
23. The value of the total vertical reaction at node 2 (R₂) = .... in (kN) is:
a) 85.5
b) 175
c) 93.75
d) 3600
d) 3600
d) 4800
d) 75.0
3
d) 0.04532
in (kN.m) is:
d) -20.50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d711242-a88c-4a58-a190-33258ba50e1c%2F371236ad-dfe2-40ef-a9e8-651f03ddd570%2F8ir8p4t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Assemble the total stiffness matrix S, the force vectors P, PFEF and the displacement vector D
for the whole structure needed to analyze the beam shown below.
Use the shown numbering system and El=constant.
1
k₁
25 kN/m
=
1
200
600
-200 600
600
k22 -600 1200
-200
-600 200 -600
600 1200 -600 2400
Answer the following questions(16-22):
6 m
17. The Value of EI= .... in (kN.m²) is:
a) 200
b) 600
(2)
2
6 m
{P} =[S]{D} + PFEF
d) 3600
c) 2400
18. For member 1, the value of K₂2 =.... in (kN.m²) is:
a) -200
b) -600
c) 2400
19. For member 2, the value of k23 = .... in (kN.m²) is:
a) -200
b) -600
c) 2400
20. For the whole structure, the value of S11
in (kN.m²) is:
b) 3600
c) 2400
a) 200
21. The rotational displacements (0₂) of node (joint) 2 = .... in (radians) is:
c) -0.03245
a) 0.0
b) 0.015625
22. The value of the moment at node 3 (M32) on the bending moment diagram =
a) 0.0
b) +18.75
c) -93.75
23. The value of the total vertical reaction at node 2 (R₂) = .... in (kN) is:
a) 85.5
b) 175
c) 93.75
d) 3600
d) 3600
d) 4800
d) 75.0
3
d) 0.04532
in (kN.m) is:
d) -20.50
Expert Solution
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Step 1: Introducing the problem statement
VIEWStep 2: To determine flexural rigidity (EI) for beam-1
VIEWStep 3: Determining k22 and k23
VIEWStep 4: Assembling global stiffness matrix
VIEWStep 5: Applying the boundary conditions
VIEWStep 6: Determining the load vector
VIEWStep 7: Applying the stiffness definition for determining joint displacement
VIEWStep 8: Determining member end actions
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