As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a = 3.0 ft, b = 8.0 ft, and c = 12.0 ft. The applied forces are F₁ = 1.00 kip and F₂ = 2.00 kip. Force F₁ is applied at an angle = 40° with the horizontal. Neglect the weight of the beam. (Figure 1) B F₂ X Part A-find the vertical component of the reaction at A Part B- Find the horizontal component of the reaction at C Part C- Find the vertical component of the reaction at C

Show a free body diagram of the left section. Find the forces in the members listed by the Method of Sections. 1. Find forces in BD, BE and CE. (T C) BD = BE = (T C) CE = (T C) 1200 1800 540 5' A 12 12' 12' 540 2075 1675 300 450 B0

PART 1 Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=2.0 m, PB = 2 kN, PC = 2 kN, and MB = 20 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.   IMAGE*   Calculate the reaction forces Ay and MA acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)   IMAGE*   PART 2 Determine the shear force acting at each of the following locations:(a) x = 0+ m (i.e., just to the right of fixed support A)(b) x = 3.5– m (i.e., just to the left of B)(c) x = 3.5+ m (i.e., just to the right of B)(d) x = 5.5– m (i.e., just to the left of C)When entering your answers, use the shear force sign convention.Answer:(a) V =  ?  kN.(b) V =  ?  kN.(c) V =  ?  kN.(d) V =  ?  kN. PART 3…

Problem 3: Inputs: a = 12 in b = 12.75 in Use the scalar approach (not the cross product). The moment exerted by the weight about point E is 244 lb-in. Table not required, but feel free to use it if you like (a) What is the magnitude of the weight? (round this answer to the nearest whole number) (b) What is the moment exerted by the weight about point S? Problem 4: Inputs: a = 1.2 m b = 0.5 m P = 50 N We are going to put this system in equilibrium. We haven't talked much about equilibrium yet, but that's okay. In order for a body to be in equilibrium, we need the sum of the forces to equal zero, and the sum of the moments about any point to equal zero. S A Table not required, but feel free to use it if you like a FA 30° a E b 40° P b (a) Let's start by summing moments about point A. Determine the magnitude of FB such that EMA = 0. In other words, compute FB such that the net moment about point A is zero. (b) Now let's repeat the process at B. Sum moments about point B and compute the…