As shown, a 3.1-lb ball is suspended at point D inside a box with dimensions w=9.50 ft, d=6.70 ft, and h=4.10 ft. The ball is held in place by three cables anchored at points A, B, and C on the surface of the box. If point D is the origin of the Cartesian coordinate system, point A is located at (−4.60,−3.50,2.50) ft, point B is located at (2.10,−3.50,1.90) ft, and point C is located at (2.10,6.00,−1.60) ft.
As shown, a 3.1-lb ball is suspended at point D inside a box with dimensions w=9.50 ft, d=6.70 ft, and h=4.10 ft. The ball is held in place by three cables anchored at points A, B, and C on the surface of the box. If point D is the origin of the Cartesian coordinate system, point A is located at (−4.60,−3.50,2.50) ft, point B is located at (2.10,−3.50,1.90) ft, and point C is located at (2.10,6.00,−1.60) ft.
Related questions
Question
100%
To determine Cartesian force components from the magnitude and determine the position and resultant vectors by summing Cartesian components.
As shown, a 3.1-lb ball is suspended at point D inside a box with dimensions w=9.50 ft, d=6.70 ft, and h=4.10 ft. The ball is held in place by three cables anchored at points A, B, and C on the surface of the box. If point D is the origin of the Cartesian coordinate system, point A is located at (−4.60,−3.50,2.50) ft, point B is located at (2.10,−3.50,1.90) ft, and point C is located at (2.10,6.00,−1.60) ft.
1) The tension in cable DA has a magnitude of TDA=7.66 lb. Find the Cartesian components of tension TDA, which is directed from D to A. so TDA=?
2)If the tensions in cables DA and DB are TDA=7.66 lb and TDB=5.56 lb, respectively, what is the tension in cable DC? so TDC=?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 17 images