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A's As,web As bw Materials: C25/30 / B420C Longitudinal reinforcements A's=2 $ 14 As,web= 2 0 12 A₁= 5 0 14 bw=300 mm d=670 mm d'=30 mm k₁= 0,85 K3 = 0,85 Pb=0.0205 (from table) Transverse Reinforcements 8/200 mm (2-leg stirrups) Material coefficients Ymc:1.5 (Concrete) Yms: 1,15 (Steel) Determine the reinforcement ratio and failure type of the beam

A's As,web As bw Materials: C25/30 / B420C Longitudinal reinforcements A's=2 $ 14 As,web= 2 0 12 A₁= 5 0 14 bw=300 mm d=670 mm d'=30 mm k₁= 0,85 K3 = 0,85 Pb=0.0205 (from table) Transverse Reinforcements 8/200 mm (2-leg stirrups) Material coefficients Ymc:1.5 (Concrete) Yms: 1,15 (Steel) Determine the reinforcement ratio and failure type of the beam

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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| * A's O As,web As bw Steel areas: A's-2 + 14 = 308 mm² A₁=50 mm² (area of $8) Materials : C25/30 / B420C Longitudinal reinforcements A's=2 $ 14 As,web= 2 $ 12 As= 5 0 14 bw=300 mm d=670 mm d'=30 mm k₁= 0,85 k3 = 0,85 Pb=0.0205 (from table) Transverse Reinforcements $8/200 mm (2-leg stirrups) Material coefficients Ymc:1.5 (Concrete) Yms: 1,15 (Steel) Determine the reinforcement ratio and failure type of the beam As,web= 212= 226 mm² Asw=2x50=100 mm² (Total Area of two leg stirrup) A₁= 5 + 14=770 mm²
Transcribed Image Text:| * A's O As,web As bw Steel areas: A's-2 + 14 = 308 mm² A₁=50 mm² (area of $8) Materials : C25/30 / B420C Longitudinal reinforcements A's=2 $ 14 As,web= 2 $ 12 As= 5 0 14 bw=300 mm d=670 mm d'=30 mm k₁= 0,85 k3 = 0,85 Pb=0.0205 (from table) Transverse Reinforcements $8/200 mm (2-leg stirrups) Material coefficients Ymc:1.5 (Concrete) Yms: 1,15 (Steel) Determine the reinforcement ratio and failure type of the beam As,web= 212= 226 mm² Asw=2x50=100 mm² (Total Area of two leg stirrup) A₁= 5 + 14=770 mm²
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