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What is SLL = ?

What is SLL = ?

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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### Transcription of Structural Engineering Calculations #### Diagram - A rectangular section is depicted with dimensions: - Height: 21 inches - Bottom gap: 3 inches - Width: 14 inches - The section includes 4 #9 rebars. #### Given Data and Calculations 1. **Material Properties:** - \( f'c = 5 \, \text{ksi} \) (Compressive strength of concrete) - Grade 60 steel - Normal Weight Concrete (NWC) - \( E_c = 4031 \, \text{ksi} \) (Modulus of elasticity of concrete) - \( f_r = 530 \, \text{psi} \) (Modulus of rupture) 2. **Ratio:** - \( N = \frac{E_s}{E_c} = 7.2 \) 3. **Moment of Inertia:** - \( I_g = \frac{1}{12} \times 14 \times 24^3 = 16128 \, \text{in}^4 \) 4. **Cracking Moment:** - \( M_{cr} = \frac{f_r I}{y} = 59.36 \, \text{ft-k} \) 5. **Structural Loading Scenario:** - A simply supported beam is drawn with an arrow indicating a load over a span of 16 feet. - Dead Load (\(W_{DL}\)) = 4.5 klf (kilo-pounds per linear foot) - Live Load (\(W_{LL}\)) = 2.5 klf 6. **Cracked Section Analysis:** - \( 14 \cdot \frac{x}{2} = 4 \times 1 \times 7.2 (21 - x) \) - Solved for \( x \): - \( 7x^2 + 28.8x - 604.8 = 0 \) - \( x = 7.46 \text{ inches} \) 7. **Moment of Inertia for the Cracked Section:** - \( I_{cr} = \frac{1}{12} \times 14 \times 7.46^3 \) - \( + 14 \times 7.46 \times
Transcribed Image Text:### Transcription of Structural Engineering Calculations #### Diagram - A rectangular section is depicted with dimensions: - Height: 21 inches - Bottom gap: 3 inches - Width: 14 inches - The section includes 4 #9 rebars. #### Given Data and Calculations 1. **Material Properties:** - \( f'c = 5 \, \text{ksi} \) (Compressive strength of concrete) - Grade 60 steel - Normal Weight Concrete (NWC) - \( E_c = 4031 \, \text{ksi} \) (Modulus of elasticity of concrete) - \( f_r = 530 \, \text{psi} \) (Modulus of rupture) 2. **Ratio:** - \( N = \frac{E_s}{E_c} = 7.2 \) 3. **Moment of Inertia:** - \( I_g = \frac{1}{12} \times 14 \times 24^3 = 16128 \, \text{in}^4 \) 4. **Cracking Moment:** - \( M_{cr} = \frac{f_r I}{y} = 59.36 \, \text{ft-k} \) 5. **Structural Loading Scenario:** - A simply supported beam is drawn with an arrow indicating a load over a span of 16 feet. - Dead Load (\(W_{DL}\)) = 4.5 klf (kilo-pounds per linear foot) - Live Load (\(W_{LL}\)) = 2.5 klf 6. **Cracked Section Analysis:** - \( 14 \cdot \frac{x}{2} = 4 \times 1 \times 7.2 (21 - x) \) - Solved for \( x \): - \( 7x^2 + 28.8x - 604.8 = 0 \) - \( x = 7.46 \text{ inches} \) 7. **Moment of Inertia for the Cracked Section:** - \( I_{cr} = \frac{1}{12} \times 14 \times 7.46^3 \) - \( + 14 \times 7.46 \times
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