what I have is working for other problems but not this one. apparently my standard deviation is off somehow following formulas I have in: standard deviation=SQRT(SUM(F77:F83)/(117-1)) As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution.-including answers submitted in WebAssign.)Milliliters of Water in the Bottle485490495500505510515What is the mean (in milliliters)?500millilitersWhat is the standard deviation (in milliliters)?8.3166X millilitersFrequencyWhat is the z value corresponding to 495 milliliters?z = -0.64209xReferring to this table, determine the A value.A = 0.2389x8122235201312Determine the probability that a bottle would be filled with more than 495 milliliters.probability=0.7389✓ Milliliters ofWater inthe bottle Frequency x*fRefer totables inproblemexamplesfor A #'s485490495500505510515485490495MeanZ500505510515Az1Milliliters of Water in thebottleRefer to tables inproblem examples for A#'schange first number in z formulato match what z score is asking for00 223 228812223512Frequency352013122013(Mean)12MeanzA₂1x-xbar (x-xbar)²+f3880500.34 -15.34 1882.98635880500.34 -10.34 1283.453910890500.3417500 500.3410100500.346630500.346180 500.34500.34-0.642090.23890.7389xbar(Mean) x f=A77 877=A78 878=A79*B79=A80*880=A81*B81=A82 882=A83*B830.2389-0.5+C87-5.34 627.78508-0.34 4.09087594.66 433.96157standarddeviation9.66 1212.630614.66 2578.3257500.34188034188-(495-500.34)/F85change first number in z formula to match what z score is asking for8.3166xbarx-xbar-SUM(C$3:C$9)/117 =A77-D77=SUM(C$3:C$9)/117 =A78-D78=SUM(C$3:C$9)/117 =A79-D79-SUM(C$3:C$9)/117 A80-D80-SUM(C$3:C$9)/117 =A81-D81-SUM(C$3:C$9)/117 A82-D82-SUM(C$3:C$9)/117 =A83-D83Answers(x-xbar) f=E77^2*877=E78^2*878=E79^2*879=E80^2 880=E81^2*881=E82^2*882=E83^2*883standard deviation -SQRT(SUM(F77:F83)/(117-1)Formulas put in

As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution. -including answers submitted in WebAssign.) Milliliters of Water in the Bottle 485 490 495 X 500 505 510 515 What is the mean (in milliliters)? 500 I milliliters What is the standard deviation (in milliliters)? 8.3166 X milliliters Frequency What is the z value corresponding to 495 milliliters? z = -0.64209 8 12 22 35 20 13 12

As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution. -including answers submitted in WebAssign.) Milliliters of Water in the Bottle 485 490 495 X 500 505 510 515 What is the mean (in milliliters)? 500 I milliliters What is the standard deviation (in milliliters)? 8.3166 X milliliters Frequency What is the z value corresponding to 495 milliliters? z = -0.64209 8 12 22 35 20 13 12

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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what I have is working for other problems but not this one. apparently my standard deviation is off somehow

following formulas I have in:

standard deviation=SQRT(SUM(F77:F83)/(117-1))

As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution.
-including answers submitted in WebAssign.)
Milliliters of Water in the Bottle
485
490
495
500
505
510
515
What is the mean (in milliliters)?
500
milliliters
What is the standard deviation (in milliliters)?
8.3166
X milliliters
Frequency
What is the z value corresponding to 495 milliliters?
z = -0.64209
x
Referring to this table, determine the A value.
A = 0.2389
x
8
12
22
35
20
13
12
Determine the probability that a bottle would be filled with more than 495 milliliters.
probability=0.7389
✓

Milliliters of
Water in
the bottle Frequency x*f
Refer to
tables in
problem
examples
for A #'s
485
490
495
500
505
510
515
485
490
495
Mean
Z
500
505
510
515
Az1
Milliliters of Water in the
bottle
Refer to tables in
problem examples for A
#'s
change first number in z formula
to match what z score is asking for
00 223 22
8
8
12
22
35
12
Frequency
35
20
13
12
20
13
(Mean)
12
Mean
z
A₂1
x-xbar (x-xbar)²+f
3880
500.34 -15.34 1882.9863
5880
500.34 -10.34 1283.4539
10890
500.34
17500 500.34
10100
500.34
6630
500.34
6180 500.34
500.34
-0.64209
0.2389
0.7389
xbar
(Mean) x f
=A77 877
=A78 878
=A79*B79
=A80*880
=A81*B81
=A82 882
=A83*B83
0.2389
-0.5+C87
-5.34 627.78508
-0.34 4.0908759
4.66 433.96157
standard
deviation
9.66 1212.6306
14.66 2578.3257
500.34188034188
-(495-500.34)/F85
change first number in z formula to match what z score is asking for
8.3166
xbar
x-xbar
-SUM(C$3:C$9)/117 =A77-D77
=SUM(C$3:C$9)/117 =A78-D78
=SUM(C$3:C$9)/117 =A79-D79
-SUM(C$3:C$9)/117 A80-D80
-SUM(C$3:C$9)/117 =A81-D81
-SUM(C$3:C$9)/117 A82-D82
-SUM(C$3:C$9)/117 =A83-D83
Answers
(x-xbar) f
=E77^2*877
=E78^2*878
=E79^2*879
=E80^2 880
=E81^2*881
=E82^2*882
=E83^2*883
standard deviation -SQRT(SUM(F77:F83)/(117-1)
Formulas put in

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