what I have is working for other problems but not this one. apparently my standard deviation is off somehow following formulas I have in: standard deviation=SQRT(SUM(F77:F83)/(117-1)) As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution.-including answers submitted in WebAssign.)Milliliters of Water in the Bottle485490495500505510515What is the mean (in milliliters)?500millilitersWhat is the standard deviation (in milliliters)?8.3166X millilitersFrequencyWhat is the z value corresponding to 495 milliliters?z = -0.64209xReferring to this table, determine the A value.A = 0.2389x8122235201312Determine the probability that a bottle would be filled with more than 495 milliliters.probability=0.7389✓ Milliliters ofWater inthe bottle Frequency x*fRefer totables inproblemexamplesfor A #'s485490495500505510515485490495MeanZ500505510515Az1Milliliters of Water in thebottleRefer to tables inproblem examples for A#'schange first number in z formulato match what z score is asking for00 223 228812223512Frequency352013122013(Mean)12MeanzA₂1x-xbar (x-xbar)²+f3880500.34 -15.34 1882.98635880500.34 -10.34 1283.453910890500.3417500 500.3410100500.346630500.346180 500.34500.34-0.642090.23890.7389xbar(Mean) x f=A77 877=A78 878=A79*B79=A80*880=A81*B81=A82 882=A83*B830.2389-0.5+C87-5.34 627.78508-0.34 4.09087594.66 433.96157standarddeviation9.66 1212.630614.66 2578.3257500.34188034188-(495-500.34)/F85change first number in z formula to match what z score is asking for8.3166xbarx-xbar-SUM(C$3:C$9)/117 =A77-D77=SUM(C$3:C$9)/117 =A78-D78=SUM(C$3:C$9)/117 =A79-D79-SUM(C$3:C$9)/117 A80-D80-SUM(C$3:C$9)/117 =A81-D81-SUM(C$3:C$9)/117 A82-D82-SUM(C$3:C$9)/117 =A83-D83Answers(x-xbar) f=E77^2*877=E78^2*878=E79^2*879=E80^2 880=E81^2*881=E82^2*882=E83^2*883standard deviation -SQRT(SUM(F77:F83)/(117-1)Formulas put in

As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution. -including answers submitted in WebAssign.) Milliliters of Water in the Bottle 485 490 495 X 500 505 510 515 What is the mean (in milliliters)? 500 I milliliters What is the standard deviation (in milliliters)? 8.3166 X milliliters Frequency What is the z value corresponding to 495 milliliters? z = -0.64209 8 12 22 35 20 13 12

As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution. -including answers submitted in WebAssign.) Milliliters of Water in the Bottle 485 490 495 X 500 505 510 515 What is the mean (in milliliters)? 500 I milliliters What is the standard deviation (in milliliters)? 8.3166 X milliliters Frequency What is the z value corresponding to 495 milliliters? z = -0.64209 8 12 22 35 20 13 12

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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